H2A (ACID) Molarity         =    0.15 M Normality N1 =    Mo.pdf

H2A (ACID)
Molarity = 0.15 M
Normality N1 = Molarity x Basicity of acid
= 0.15x 2
= 0.3 N
Volume V1 = 100 ml
N1V1 = 0.3 x 100 = 30
NaOH (BASE)
Molarity = 0.16 M
Normality N2 = Molarity xAcidity of Base
= 0.16 x 1
= 0.16 N
Volume V2 = 100 ml
N2V2 = 0.16X100 = 16
Since concentration of ACID is more than concentration of BASE, resulatant concentration is
equal to
H+ ion concentration.
Normality at eqivalance point N = (N1V1 - N2V2)/ (V1+V2)
= 30 - 16/(100+100)
= 14/200
= 0.07 N
= H+ ion concentartion
Solution
H2A (ACID)
Molarity = 0.15 M
Normality N1 = Molarity x Basicity of acid
= 0.15x 2
= 0.3 N
Volume V1 = 100 ml
N1V1 = 0.3 x 100 = 30
NaOH (BASE)
Molarity = 0.16 M
Normality N2 = Molarity xAcidity of Base
= 0.16 x 1
= 0.16 N
Volume V2 = 100 ml
N2V2 = 0.16X100 = 16
Since concentration of ACID is more than concentration of BASE, resulatant concentration is
equal to
H+ ion concentration.
Normality at eqivalance point N = (N1V1 - N2V2)/ (V1+V2)
= 30 - 16/(100+100)
= 14/200
= 0.07 N
= H+ ion concentartion.

1. H2A (ACID)

Molarity         =    0.15 M

Normality N1 =    Molarity x Basicity of acid

                     =   0.15x 2

                     =   0.3 N

Volume V1      =   100 ml

N1V1 =   0.3 x 100 = 30
NaOH (BASE)

Molarity        = 0.16 M

Normality N2 = Molarity xAcidity of Base

                   = 0.16 x 1

                  = 0.16 N

Volume    V2 = 100 ml


N2V2 =   0.16X100 = 16



Since concentration of ACID is more than concentration of BASE, resulatant concentration is
equal to

H+ ion concentration.

2. Normality at eqivalance point N = (N1V1 - N2V2)/ (V1+V2)

                                        = 30 - 16/(100+100)

                                        = 14/200

                                        = 0.07 N

                                        = H+ ion concentartion

Solution

H2A (ACID)

Molarity         =    0.15 M

Normality N1 =    Molarity x Basicity of acid

                     =   0.15x 2

                     =   0.3 N

Volume V1      =   100 ml

N1V1 =   0.3 x 100 = 30
NaOH (BASE)

Molarity        = 0.16 M

Normality N2 = Molarity xAcidity of Base

                   = 0.16 x 1

                  = 0.16 N

Volume    V2 = 100 ml

3. N2V2 =   0.16X100 = 16



Since concentration of ACID is more than concentration of BASE, resulatant concentration is
equal to

H+ ion concentration.

Normality at eqivalance point N = (N1V1 - N2V2)/ (V1+V2)

                                        = 30 - 16/(100+100)

                                        = 14/200

                                        = 0.07 N

                                        = H+ ion concentartion