2.1. Introduction to modulation
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What is Modulation?
Modulationis the process of encoding information from a message
source in a manner suitable for transmission
•isusedtocontroltheparametersofacarriersignal.
•Encodinginformationinasuitableformfortransmission.
Translatebasebandsourcesignaltobandpasssignal
Bandpasssignal:“modulatedsignal”
•Howsignalmodulate?-Varyamplitude,phaseorfrequencyofacarrier
WhatisDemodulation?
•Decodingorextractbasebandmessagefromcarrier
•isthereverseprocessofmodulationtorecoverthemessagesignal
m(t)ord(t)atthereceiver
Con’t
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2.2. Linear modulations and demodulations
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2.2.1. Classification of Modulation
1.Analog Modulation
•Modulating (m(t)):
✓The input signal is continuous signal
2.Digital Modulation
•Modulating (d(t)):
✓The input is time sequence of symbols or pulses
d(t)
d(t)
d(t)
•ASK
•FSK
•PSK
•QAM
con’t
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6
•Type of analog modulation
Amplitude Modulation (AM)
Frequency Modulation (FM)
Phase modulation (PM)
•Amplitude Modulation (AM)
linear dependence on quality & power of rcvd signal
The out signal is continuous and increased in strength
The modulating signal m(t) is 'impressed' on to the amplitude of the carrier
m(t)
m(t)
m(t)
•AM
•DSB
•DSB-SC
•SSB
•VSB
Con’t
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7
•
Amplitude Modulation
•The amplitude of high-carrier signal is varied according to the
instantaneous amplitude of the modulating message signal m(t).)2cos()](1[)(
)(
)2cos(
:Signal AM The
:Signal Message Modulating
:SignalCarrier
tftmAts
tm
tfA
ccAM
cc
+=
AM Modulator s
AM(t)m(t)
Con’t
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8
NB:
USB-upper side band
LSB-lower side band
•Nowletm(t)=V
mcos
mt,i.e.a'test'signal
•Usingthetrig-identity
•wehave() () ()()tωtωV+tωV=tv
cmmcCs coscoscos ( ) ( ) BA+B+A=BA −coscos
2
1
coscos () () ( )( ) ( )( )tωω
V
+tω+ω
V
+tωV=tv
mc
m
mc
m
cCs −cos
2
cos
2
cos
Comments Carrier USB LSB
Amplitude V
C V
m/2 V
m/2
Frequency f
c f
c+ f
m f
c-f
m
Angular
frequency
c
c+
m
c–
m
•This equation represents Double Side Band Amplitude Modulation
DSBAM
The modulationindex.c
m
A
A
m=
Amplitude modulation
Con’t
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9
•
Con’t
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10
•
The total bandwidth required for AM
can be determined
from the bandwidth of the Message
signal: B
AM= 2B. Where, B is the bandwidth
of the message signal m(t)
1Thecarriersignalisccccc
ftAts 2 where)cos()( ==
2In the same way, a modulating signal(information
signal) can also be expressed as tAts
mmm
cos)(=
Derive the Frequency Spectrum for Full-AM
Modulation (DSB-LC)
1/17/2021 11by Getachew
3The amplitude-modulated wave can be expressed as )cos()()( ttsAts
cmc
+= )cos()cos()( ttAAts
cmmc
+=
4 By substitution of the message signalc
m
A
A
m=
5 The modulation index.
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6 Therefore The full AM signal may be
written as)cos())cos(1()( ttmAts
cmc
+= )]cos()[cos(2/1coscos BABABA −++= t
mA
t
mA
tAts
mc
c
mc
c
cc )cos(
2
)cos(
2
)(cos)( −+++=
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f
C f
c+f
mf
c-f
m
2f
m
Draw the Frequency Spectrum of the above AM
signal and calculate the Bandwidth
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ThefrequencyspectrumofAMwaveformcontains
threeparts:
1.Acomponentatthecarrierfrequencyf
c
2.Anuppersideband(USB),whosehighest
frequencycomponentisatf
c+f
m
3.Alowersideband(LSB),whosehighestfrequency
componentisatf
c-f
m
Thebandwidthofthemodulatedwaveformistwicethe
informationsignalbandwidth.
Frequency Spectrum of an AM signal
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Con’t 19
1/17/2021
PowerinDSBAM
•NormalisedAveragePower=(V
RMS)
2
/R=
•wemaytabulateforAMcomponentsasfollows:
•Fromthiswemaywritetwoequivalentequationsforthetotalpower
P
T,inaDSBAMsignal
•ThecarrierpowerR
V
pk
/
2
2
() () ( )( ) ( )( )tωω
V
+tω+ω
V
+tωV=tv
mc
m
mc
m
cCs −cos
2
cos
2
cos 4R2R8R8R2R
22222
mCmmC
T
V
+
V
=
V
+
V
+
V
=P
and8R8R2R
22222
CCC
T
Vm
+
Vm
+
V
=P 2R
2
C
c
V
=P
i.e.44
22
m
P+
m
P+P=P
cccT
or
2
1
2
m
+P=P
cT
Con’t 20
1/17/2021
Component Carrier USB LSB
Amplitude pk
V
C
Power
Power2
mV 2
mV 2R
2
CV 8R22R
22
mm V
=
V
8R
22
CVm
Total Power P
T= Carrier Power P
c+ P
USB+ P
LSB8R22R
22
mm V
=
V
2R
2
C
V 8R
22
C
Vm
Con’t 21
1/17/2021
•Eitheroftheseformsmaybeuseful.SincebothUSBandLSBcontainthe
sameinformationausefulratiowhichshowstheproportionof'useful'power
tototalpoweris
•ForDSBAM(m1),allowingform(t)withadynamicrange,theaverage
valueofmmaybeassumedtobem=0.3
•Hence,onaverageonlyabout2.15%ofthetotalpowertransmittedmayberegarded
as'useful'power.(95.7%ofthetotalpowerisinthecarrier!)
•Evenforamaximummodulationdepthofm=1forDSBAMtheratio2
2
2
2
24
2
1
4
m+
m
=
m
+P
m
P
=
P
P
c
c
T
USB
Hence, ()
()
0.0215
0.324
0.3
24
2
2
2
2
=
+
=
m+
m 6
1
24
2
2
=
m+
m
i.e.only1/6thofthetotalpoweris'useful'power(with2/3of
thetotalpowerinthecarrier).
Con’t 22
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Example 2
•IfthecarrierofanAMtransmitteris1000wanditismodulated100%,
a)findthetotalpower
b)PowerinDSBandpowerinoneSB
•ThecarriercomponentinfullAMorDSB-LCdoesnotconveyany
information.Henceitmayberemovedorsuppressedduringthe
modulationprocesstoattainhigherpowerefficiency.
•ThetradeoffofachievingahigherpowerefficiencyusingDSB-SC
isattheexpenseofrequiringacomplexandexpensivereceiverdue
totheabsenceofcarrierinordertomaintaintransmitter/receiver
synchronization.
Double Side Band Suppressed Carrier
(DSB-SC) Modulation
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1Considerthecarrierccccc
ftAts 2 where)cos()( ==
2modulated by a single sinusoidal signalmmmm
ftAts 2 wherecos)(
m
==
3Themodulatedsignalissimplytheproductofthesetwo( )
LSB
mc
cm
USB
mc
cm
mcmc
mmcc
t
AA
t
AA
BABABA
ttAA
tAtAts
)cos(
2
)cos(
2
)cos()cos(
2
1
coscos since
)cos()cos(
)cos()cos()(
−++=
−++=
=
=
Derive the Frequency Spectrum for Double
Sideband Suppressed Carrier Modulation (DSB-
SC)
1/17/2021 24by Getachew
tAts
mmm
cos)(= tAts
ccc
cos)(= )cos()cos()( tAtAts
mmcc
= X
f
c
f
c-f
m f
c+f
m
Frequency Spectrum of a DSB-SC AM Signal
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Single-Sideband Modulation
How to generate SSB signal?
•Generate DSB-SC signal
•Band-pass filter to pass only one of the sideband
and suppress the other.
For the generation of an SSB modulated signal
to be possible, the message spectrum must have
an energy gap centered at the origin.
Single Side Band Modulation (SSB)
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Con’t 33
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Power in SSB
•Frompreviousdiscussion,thetotalpowerintheDSBsignalis
•Hence,ifP
candmareknown,thecarrierpowerandpowerinonesideband
maybedetermined.Alternatively,sinceSSBsignal
•thenthepowerinSSBsignal(NormalisedAveragePower)is
•PowerinSSBsignal=
2
1
2
m
+P=P
cT 44
22
m
P+
m
P+P=P
cccT=
for DSBAM.() () ( )( )tω+ω
V
+tωV=tv
mc
m
cCs cos
2
cos 8R2R22R2R
2222
mCmC
SSB
V
+
V
=
V
+
V
=P
)
4
1(
8R2R
222
m
P
V
+
V
c
mC
+=
Vestigial Side Band (VSB) Modulation
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Vestigial Side Band (VSB) Modulation
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Con’t
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36
Percentage of Modulation
•modulatingsignalvoltageVmmustbelessthanthecarriervoltageVc.
•relationshipbetweentheamplitudeofthemodulatingsignalandthe
amplitudeofthecarriersignal,knownasthemodulationindexm(also
calledthemodulatingfactororcoefficient,orthedegreeofmodulation),is
theratio
•Thesearethepeakvaluesofthesignals,andthecarriervoltageistheun
modulatedvalue.
•Multiplyingthemodulationindexby100givesthepercentageof
modulation.
•Forexample,ifthecarriervoltageis9Vandthemodulatingsignalvoltage
is7.5V,themodulationfactoris0.8333andthepercentageofmodulationis
0.8333*100=83.33%.c
m
V
V
=m
Comparison of Amplitude Modulation methods
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