Pythagoras’ Theorem Objectives Know the Pythagoras’ Theorem Understand how to use the theorem to find missing lengths Be able to solve problems using Pythagoras’ Theorem
For any right-angled triangle with hypotenuse . Hypotenuse (the longest side) ! Take note Pythagoras’ Theorem Note : notice that it is the longest side that’s on its own on one side of the equation. The (squared) shorter sides are the ones that are added.
Step 1: Determine the hypotenuse. Step 2: Form an equation Step 3: Solve the equation to find the unknown side. or 4.47 to 2dp The hypotenuse appears on its own. Example ? ? Reveal >
Step 1: Determine the hypotenuse. Step 2: Form an equation Step 3: Solve the equation to find the unknown side. or 6.32 to 2dp The hypotenuse appears on its own. Further Example ? ? Reveal >
Test Your Understanding Work out the missing values.
Harder Questions There’s a variety of ways in which Pythagoras questions could get harder: 6 3 4 Multiple triangles chained together. A B Adding lines to form right-angled triangles that weren’t originally there. Area? 2 2 2 3 7 9 C Requiring algebraic manipulation.
E xample 1 Calculate the length DB
Test Your Understanding Calculate the length of x.
Pythagorean Triples Pythagorean Triples are three positive integers that satisfy the Pythagorean Theorem.
✎ Your Task Worksheet
Challenge Task
Plenary: Give your answer to 3 s.f. Work out the length BC. Work out the value of y. and cm. Find the sides of the triangle.
Plenary: Give your answer to 3 s.f. Work out the length BC. Work out the value of y. and cm. Find the sides of the triangle. Ans: 27.3 mm Ans: 3.63 cm
Learning Outcomes I k now the Pythagoras’ Theorem I u nderstand how to use the theorem to find missing lengths I am able to solve problems using Pythagoras’ Theorem
Pythagoras’ Theorem in 3D Objective Be able to apply Pythagoras’ Theorem in problems involving 3D.
Calculate the length BH. A H G F E D C B 10cm 4cm 8cm 4cm 10cm H F E FH 2 = 4 2 + 10 2 FH 2 = 16 + 100 FH 2 = 116 FH = √116 Pythagoras’ Theorem in 3D
Calculate the length BH. A H G F E D C B 10cm 4cm 8cm 8cm √116cm H B F BH 2 = 8 2 + (√116) 2 BH 2 = 64 + 116 BH 2 = 180 BH = √180 BH = 13.4cm (3 s.f. ) Pythagoras’ Theorem in 3D
Pythagoras’ Theorem in 3D – Fast Way!
Pythagoras’ Theorem in 3D – Fast Way!
A square based pyramid has a base with side lengths 5cm and sloping sides of length 13cm. It has a vertex O and the midpoint of the base is at M vertically below O. Calculate the lengths: i ) AM and ii) OM A B D C O M 5cm 13cm 13cm O M A We can’t calculate AM since we don’t know OM yet! We need to work out AC first. Pythagoras’ Theorem in 3D
A B D C O M 5cm 13cm 5cm 5cm D C A AC 2 = 5 2 + 5 2 AC 2 = 25 + 25 AC 2 = 50 AC= Therefore, AM = Pythagoras’ Theorem in 3D
13cm M O A 13 2 = + OM 2 169 = + OM 2 = OM 2 = OM 2 OM = 12.5cm (3 s.f. ) A B D C O M 5cm 13cm Pythagoras’ Theorem in 3D