A = 1 B = 2 C = 3 D = 4 E = 5 F = 6 G = 7 H = 8 I = 9 J = 10 K = 11 L = 12 M = 13 N = 14 O = 15 P = 16 Q = 17 R = 18 S = 19 T = 20 U = 21 V = 22 W = 23 X = 24 Y = 25 Z = 26
R A T E 44
P E C E R N T 81
P R I A N P C I L 98
S I P M L E 74
V A L U E 61
I N E R T E S T 110
L O A N 42
C O P O M U N D 101
T I M E 47
I N V E S T M E T N 141
Illustrate Simple Interest Math of Investment
OBJECTIVES: Define and Illustrate Simple Interest, Compute interest, maturity value, future value, and present value in simple interest, Solve problems involving simple interest. 1 3 2
TIME (t) DEFINITION OF TERMS: REPAYMEMENT DATE OR MATURITY DATE Date on which the money borrowed, or loan is to be completely repaid. Amount of time in years the money is borrowed or invested; length of time between the origin and maturity dates.
RATE (r) DEFINITION OF TERMS: PRINCIPAL (P) Amount of money borrowed or invested on the origin date. Annual rate, usually in percent , charge by the lender, or rate in increase of the investment.
SIMPLE INTEREST ( ) DEFINITION OF TERMS: INTEREST (I) Amount paid or earned for the use of money. Interest that is computed on the principal and then added to it.
MATURITY VALUE OR FUTURE VALUE (A) DEFINITION OF TERMS: COMPUND INTEREST ( ) Interest is computed on the principal and also on the accumulated past interest. Amount after t years that the lender receives from the borrower on the maturity date.
SIMPLE INTEREST Simple Interest is charged only on the loan amount called the principal . Thus, interest on the interest previously earned is not included. Simple Interest is calculated by multiplying the principal by the rate of interest by the number of payment periods in a year. I = Prt
I P r t I = interest P = Principal r = rate of interest t = time P = r = t =
Let’s Practice
Example 1: Theressa borrowed Php 120,000.00 from her uncle. If Theressa agreed to pay an 8% annual interest rate, calculate the amount of interest she must pay if the loan period is (a) 1 year, (b) 9 months, (c) 18 months.
Solution: Given: P = 120,000 r = 8% or 0.08 t = 1 year t = 9 months t = 18 months Formula: I = Prt I = Prt I = 120,000 (0.08) (1) I = 9,600 I = Prt I = 120,000 (0.08) ( ) I = 7,200 I = Prt I = 120,000 (0.08) ( ) I = 14,400
Example 2: To buy the school supplies for the coming school year, you get a summer job at a resort. Suppose you save Php 4,200.00 of your salary and deposit it into an account that earns simple interest. After 9 months, the balance is Php 4,263.00. What is the annual interest rate?
Solution: Given: P = 4,200 I = 4,263 – 4,200 = 63 t = 9 months or or Formula: r = r = r = r = 0.02 or 2%
Example 3: If Php 10,000.00 is invested at 4.5% simple interest, how long will it take to grow to Php 11,800.00 ?
Solution: Given: P = 10,000 I = 11,800 – 10,000 = 1,800 r = 4.5% or 0.045 Formula: t = t = t = t = 4
MATURITY VALUE A = P(1 + rt )
Example 1: A loan institution charges 12% simple interest for 3 years, Php 60,000.00 loan. a. Find the total interest on the loan. b. Find the total amount that must be paid to the loan institution at the end of 3 years.
Solution: Given: P = 60,000 r = 12% or 0.12 t = 3 years Formula: I = Prt I =(60,000) (0.12)(3) I = 21,600
Solution: Given: P = 60,000 r = 12% or 0.12 t = 3 years Formula: A = P( 1 + rt ) A = 60,000 A = 81,600 A = 60,000 (1.36)