Mass & Heat Transfer/Mass & Heat Transfer.pptx

JunaidKhan728131 71 views 23 slides Jul 04, 2024
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About This Presentation

Mass & Heat Transfer


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Chilton and Colburn J-factor analogy Recall: The equation for heat transfer in the turbulent regime Sieder -Tate Equation     (for forced convection/ turbulent, Re > 10000 & 0.5 < Pr < 100) If we divide this by    

Dimensionless Groups Dim. Group Ratio Equation Prandtl , Pr molecular diffusivity of momentum / molecular diffusivity of heat Schmidt, Sc momentum diffusivity/ mass diffusivity Lewis, Le thermal diffusivity/ mass diffusivity Stanton, St heat transferred/ thermal capacity Nusselt , Nu convective / conductive heat transfer across the boundary Dim. Group Ratio Equation Prandtl , Pr molecular diffusivity of momentum / molecular diffusivity of heat Schmidt, Sc momentum diffusivity/ mass diffusivity Lewis, Le thermal diffusivity/ mass diffusivity Stanton, St heat transferred/ thermal capacity Nusselt , Nu convective / conductive heat transfer across the boundary

Chilton and Colburn J-factor analogy This can be rearranged as       For the turbulent flow region, an empirical equation relating f and Re

Chilton and Colburn J-factor analogy     This is called as the J-factor for heat transfer

Chilton and Colburn J-factor analogy In a similar manner, we can relate the mass transfer and momentum transfer using   the equation for mass transfer of all liquids and gases If we divide this by    

Chilton and Colburn J-factor analogy T        

Chilton and Colburn J-factor analogy   This is called as the J-factor for mass transfer  

Chilton and Colburn J-factor analogy Extends the Reynolds analogy to liquids    

Chilton and Colburn J-factor analogy If we let         Applies to the following ranges: For heat transfer:10,000 < Re < 300,000 0.6 < Pr < 100 For mass transfer: 2,000 < Re < 300,000 0.6 < Sc < 2,500  

Martinelli Analogy Reynolds Analogy  demonstrates similarity of mechanism (the gradients are assumed equal)  Pr = 1 and Sc = 1 Chilton-Colburn J-factor Analogy  demonstrates numerical similarity (implies that the correlation equations are not faithful statements of the mechanism, but useful in predicting numerical values of coefficients  wider range of Pr and Sc

Martinelli Analogy Martinelli Analogy (heat and momentum transfer)  applicable to the entire range of Pr number Assumptions: The T driving forces between the wall and the fluid is small enough so that μ / μ 1 = 1 Well-developed turbulent flow exists within the test section Heat flux across the tube wall is constant along the test section Both stress and heat flux are zero at the center of the tube and increases linearly with radius to a maximum at the wall At any point ε q = ε τ

Martinelli Analogy Assumptions: 6. The velocity profile distribution given by Figure 12.5 is valid

Martinelli Analogy     Both equal to zero; For cylindrical geometry

Martinelli Analogy     Both equal to zero; For cylindrical geometry Integrated and expressed as function of position Converted in the form  

Martinelli Analogy

Martinelli Analogy Martinelli Analogy (heat and momentum transfer)  applicable to the entire range of Pr number  predicts Nu for liquid metals  contributes to understanding of the mechanism of heat and momentum transfer

Martinelli Analogy Martinelli Analogy (heat and momentum transfer)  applicable to the entire range of Pr number  predicts Nu for liquid metals  contributes to understanding of the mechanism of heat and momentum transfer

Analogies EXAMPLE Compare the value of the Nusselt number, given by the appropriate empirical equation, to that predicted by the Reynolds, Colburn and Martinelli analogies for each of the following substances at Re= 100,000 and f = 0.0046. Consider all substances at 100 F, subject to heating with the tube wall at 150 F.

Example Sample Calculation For air,      

Example Sample Calculation For air, by Reynolds analogy      

Example Sample Calculation For air, by Colburn analogy          

Example Sample Calculation For air, by Martinelli analogy  

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