MATH 8-LESSON 1fdghhrjkhjkrhejksfhjkdsh7.pdf

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1. MATH 8
TOPIC: SLOPE OF A LINE

2. Slope of a Line
Slope basically describes the
steepness of a line

3. If a line goes up from left to right, then the slope
has to be positive
Conversely, if a line goes down from left to right,
then the slope has to be negative

4. Definitions of Slope
Slope is simply the change in the
vertical distance over the change in
the horizontal distance12
12
xx
yy
x
y
run
rise
mslope







5. 12
12
xx
yy
m


 The formula above is the one which we will use
to find the slope of specific lines
In order to use that formula we need to know,
or be able to find 2 points on the line

6. If a line is in the form Ax + By = C,
we can use the following formula to
find the slope:B
A
m

7. Examples

3
1
6
2
15
46
6,5,4,1





m
m 3
2
532



m
yx

8. SEATWORK12
12
xx
yy
m




9. Horizontal lines have a slope of zero
while vertical lines have no slope
Horizontal
y=
Vertical
x=
m = 0
m = no
slope

10. The World Of Linear
Equations
Writing Linear Equations
In Slope-Intercept Form
y = mx + b

11. If you are given:
The slopeand y-intercept
●Finding the equation of
the line in y= mx + b
form. Given: slope and
y-intercept.Just
substitute the “m” with the
slope value and the “b”
with the y-intercept value.
●Slope = ½ and
●y-intercept = -3
y= mx + b
½
-3
y= ½x –3

12. If you are given: A Graph
Find the:
●y –intercept= b = the point
where the line crosses the y axis.
●Slope= = m = run
rise sx'inchange
sy'inchange
y –intercept= b = -3
Slope= = m = ½
y= mx + b2 over
1 up
½
-3
y= ½x –3

13. If you are given:
The slopeand a point
●Given: slope (m) and
a point (x,y).To write
equations given the
slope and a point
using Point-Slope
Form.
●Slope =½ and point (4,-1)11
y y m(x x )   ½ 4-1
y= ½x –3
Point-Slope Form11
y y m(x x )     4
2
1
1  xy  4
2
1
1  xy 2
2
1
1  xy
-1 -1

14. If you are given:
Two points
●Finding the equation of
the line in y= mx + b
form. Given: Two
points.First find the
slope (m)and then
substitute one of the
points x and y values
into Point-Slope Form.sx'inchange
sy'inchange 11
y y m(x x )  
Point-Slope Form
Point (-2, -4) & Point (2, -2)
Find the:
Slope= = m =run
rise 




22
42 


22
42 2
1
4
2

Slope =½ and point (2, -2)11
y y m(x x )     2
2
1
2  xy 1
2
1
2  xy
-2 -2
y= ½x –3