(NH4)2SO4 is a soluble salt and is fully ionized in solution(NH4).pdf

(NH4)2SO4 is a soluble salt and is fully ionized in solution:
(NH4)2SO4 => 2 NH4+ + SO42-
NH4+ is a weak acid and ionizes further: NH4+ NH3 + H+
The H+ formed can react with C2O42- to form the weak acid oxalic acid (H2C2O4):
C2O42- + 2 H+ H2C2O4
Removal of C2O42- causes the equilibrium: ZnC2O4 Zn2+ + C2O42-
to shift to the right according to Le Chatelier\'s principle and more ZnC2O4 dissolves.
Thus the solubility of ZnC2O4 increases in the presence of (NH4)2SO4.
Solution
(NH4)2SO4 is a soluble salt and is fully ionized in solution:
(NH4)2SO4 => 2 NH4+ + SO42-
NH4+ is a weak acid and ionizes further: NH4+ NH3 + H+
The H+ formed can react with C2O42- to form the weak acid oxalic acid (H2C2O4):
C2O42- + 2 H+ H2C2O4
Removal of C2O42- causes the equilibrium: ZnC2O4 Zn2+ + C2O42-
to shift to the right according to Le Chatelier\'s principle and more ZnC2O4 dissolves.
Thus the solubility of ZnC2O4 increases in the presence of (NH4)2SO4..

1. (NH4)2SO4 is a soluble salt and is fully ionized in solution:
(NH4)2SO4 => 2 NH4+ + SO42-
NH4+ is a weak acid and ionizes further: NH4+<=> NH3 + H+
The H+ formed can react with C2O42- to form the weak acid oxalic acid (H2C2O4):
C2O42- + 2 H+ <=> H2C2O4
Removal of C2O42- causes the equilibrium: ZnC2O4 <=> Zn2+ + C2O42-
to shift to the right according to Le Chatelier\'s principle and more ZnC2O4 dissolves.
Thus the solubility of ZnC2O4 increases in the presence of (NH4)2SO4.

Solution

(NH4)2SO4 is a soluble salt and is fully ionized in solution:
(NH4)2SO4 => 2 NH4+ + SO42-
NH4+ is a weak acid and ionizes further: NH4+<=> NH3 + H+
The H+ formed can react with C2O42- to form the weak acid oxalic acid (H2C2O4):
C2O42- + 2 H+ <=> H2C2O4
Removal of C2O42- causes the equilibrium: ZnC2O4 <=> Zn2+ + C2O42-
to shift to the right according to Le Chatelier\'s principle and more ZnC2O4 dissolves.
Thus the solubility of ZnC2O4 increases in the presence of (NH4)2SO4.