ORIFICE (STEADY FLOW) VELOCITY Theoretical Velocity Actual Velocity v = Cv DISCHARGE Theoretical Discharge Actual Discharge Q = C TOTAL HEAD H = )
DEVICE COEFFICIENTS Coefficient of Discharge C = Coefficient of Velocity Coefficient of contraction Cc = C = Cc
DIFFERENT HEADS
PROBLEM 1 – Orifice (Constant head) An orifice having an area of 0.00982 is attached to a vertical side of a cylindrical tank having diameter of 4 m. The weight of the water discharge in 1 minute and 36 seconds is 22571 N under a constant head of 1.2 m and 1.92 m horizontally from the vena contrata 0.8 m vertically below the orifice. a.) Compute the coefficient of velocity. b.) Compute the coefficient of discharge. c.) Compute the coefficient of contraction.
PROBLEM 1 – Orifice (Constant head)
PROBLEM 2 – Orifice (Constant head) An open cylindrical tank, 2.4 m in diameter and 6m tall has 1 m of glycerine sp.gr = 1.5, 2.5 m of water, and 1.5 m of oil (sp.gr = 0.82). Determine the discharge through the 125 mm diameter located at the bottom of the tank. Assume C = 0.65
ORIFICE (UNSTEADY FLOW) AREA IS VARYING AREA IS CONSTANT TWO TANKS HAVE UNIFORM CROSS SECTIONAL AREA
PROBLEM 1 – Orifice (Falling head) A 1.5 m diameter vertical cylindrical tank 3 m high contains 2.5 m of water. A 100 – mm diameter circular sharp – edged orifice is located at the bottom. Assume C = 0.6. a.) How long will it take to lower the water level to 1 m deep after opening the orifice. b.) How long will it take to empty the tank?
PROBLEM 1 – Orifice (Falling head)
PROBLEM 2 – Orifice (Falling head) A tank with a frustum of a cone having its bases horizontal and axis vertical is 3 m high and is filled with water. It has a diameter of 2 m at the top and 1 m at the bottom. C = 0.61. What size of the orifice will empty the tank in 6 mins and 29 seconds?