PPT for science 9 projectile motion.pptx

A PPT for Projectile Motion

1. s

2. projectile - an object trajectory - the
undergoing projectile Y parabolic path taken
i - © + © & by a projectile

o \ PARABOLA
N

\
j N
0

angle (6) - a numerical value
in degrees (°) expressing the
orientation of the projectile to
be thrown/projected

3. ペー テー HORIZONTALLY
LAUNCHED
PROJECTILES

ANGLE LAUNCHED
PROJECTILES

4. HORIZONTAL MOTION

X-component

v” Neglect air resistance.

< There is a constant horizontal velocity.
(Ve)

Y Horizontal acceleration is 0. ax = 0

v We call the horizontal distance as RANGE.

(dy

5. VERTICAL MOTION
Y-component
The force acting upon in this motion is the force of
(9 = a, =a,) (9 = -9.8m/s?)
/ Vertical velocity is not constant. Vy

( We call the vertical distance as the height.

h=d,

6. Vx - horizontal velocity responsible
for the projectile to travel ata
horizontal distance

Vy - vertical velocity responsible for

the projectile to travel at a vertical

height - the vertical distance

distance from the
projectile to the earth's
surface

#…

Vy

range - horizontal distance covered by |
the projectile

7. A core is CET
horizontally from a tabletor
with a velocity of 1.50m/s.
The marble falls 0.70 m
away the table's edge.
Find the ff:
a) How high is the table?
b) What is the final
velocity of the marble
just before it hits the

cup? a

8. A AAA

—WxV¡=1.50m/s | |
E i ・ A marble is thrown
= = horizontally from a tabletop
| with a velocity of 1.50m/s.

The marble falls 0.70 m
away the table's edge.
Find the ff:
の a) How high is the table?
b) What is the final
velocity of the marble
just before it hits the
cup?

==

9. d, = 0.70m
V; = 1.50 m/s
ay = 9.8 m/s?

a) How high is the table?

0.70
C="Ts0m/s の
y
t=0.47 s
a,

dy

dy = y, agt?

d
V;

(9.8 m/s?) (0.475)?

_ (98 mie) (0.220957)
2

2.16482 m /2
1.08 m

10. ax = 0.70m Formula: |YR = /Vfy? + Vfx2

Vix = 1.50 m/s
ay = 9.8 m/s?
dy = 1.08m Take note: (a,= 9)

b) What is the final velocity of the marble just before it hi
the cup?

Vey テーy(2)(9.8 m/s?)(1.08 m)
Yy=- [21.168 me/ 了

Vpy =-4.6 m/s (-) indicates downward direction

11. ıven

dx = 0.70 m Formula:|Vp = /Vfy2 +Vfx2
Vix = 1.50 m/s Es ty f

= 2
% Em Take note: V; = Vix = Vrx = We

Vey = 一 4.6 m/s
b) What is the final velocity of the marble just before it hits
the cup?

Va= J(-4.6 m/s)? + (1.50 m/s)?

Va ニー 21.16 m?/s? + 2.25 m?/s?
Va= 23.41 m/s?

Ve= 4.84m/s

12. (displacement)

Vi (initial Velocity)

Vy (Final Velocity)

Viy = — |2gdy

(-) sign means downward direction

a,=0 a,=g
€ ( Acceleration)
d
t=> za,
E (Time) P t= PA

VD (Resultant Velocitv)

VR = \Vfy? + Vf?