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About This Presentation

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Slide Content

YOUNG STARS INSULATORS Presented by k.Nagasaravanan Karthick raja D.s.mukesh

CONTENTS. What is insulators Types of insulators Causes of failure of insulators String efficiency Potential distribution over suspension insulator string One mark q&a 12 mark q&a Reference

WHAT IS INSULATORS The overhead lines conductors should be supported on the poles or towers in such way that current from conductors do not flow to earth through support.

Properties of insulators . High mechanical strength in order to withstand conductor load , wind load. High electrical resistance of insulator material in order to avoid leakage current to earth. High relative permittivity of insulator material in order that di-electric strength is high. The insulator materials should be non-porous , free from impurities and cracks otherwise the permittivity will be lower. High ratio of puncture strength to flashover.

TYPES OF INSULATORS . Pin type insulators Suspension type insulators Strain insulators Shackle insulators

PIN TYPE INSULATORS . A Pin insulator consists of non- conducting material such as glass, porcelain , wood ,polymer and plastic . As the name suggest , the pin type insulator is secured to the cross-arm pole . There is a groove on the upper end of the insulator for housing the conductor. The conductor passes through this groove and this bound by the annealed wire of the same material as the conductors.

Pin insulator are used for transmission and distribution of electric power at voltage up to 33kv Beyond operating voltage of 33 kv , the pin type insulator become too bulky and uneconomical

DIAGRAM FOR PIN INSULATOR

CAUSES OF INSULATOR FAILURE . Insulators are required to withstand both mechanical and electrical stresses . The ladder type is primarily due to line voltage and may cause the breakdown of the insulator. The electrical break down of the insulator can occurs either by puncture. In flash over , an arc occurs between the line conductor and I hsulator pin and the discharge jumps. In case of flash over , the insulator will continue to act in its proper capacity unless extreme produced by arc destroys the insulator. safety factor of insulator = puncture strength flash – over voltage

SUSPENSION INSULATOR . The cost of pin type insulator increases rapidly as the working voltage is increased. This type of insulator is not economical beyond 33kv . They consist of a number of proceleain discs connected in series by metal links in the form of a strings. The conductor is suspended at the bottom end of the string while the other end of the strings is secured to the cross-arm of the tower. The working voltage is 66kv ,then six discs in series will be provided on the string.

DIAGRAM FOR SUSPENSION INSULATOR .

ADVANTAGES Suspension type insulators are cheaper than pin type insulators for voltages beyond 33kv . Each unit or disc of suspension type insulator is designed for low voltage , usually 11kv.depending upon the working voltage , the desired number of discs can be connected in series. If any one disc is damaged , the whole string does not become useless because the damaged disc can be replaced by the sound one.

Cont…. The suspension arrangement provides greater flexibility to the line . The connection at the cross arm is such that insulator string is free to swing in any direction and can take up the position where mechanical stresses are minimum. In case of increased demand on the transmission line, it is found more satisfactory to supply the greater demand by raising the line voltage than to provide another set of conductor. The suspension type insulators are generally used with steel towers. As the conductors below the earthed cross-arm of the tower , therefore , this arrangement provides partial protection from lightning .

STRAIN INSULATOR When there is a dead end of the line or there is corner or sharp curve, the line is subjected to greater tension. In order to relieve the line of excessive tension , strain insulators are used. For low voltage lines (< 11 kV), shackle insulators are used as strain insulators. However, for high voltage transmission lines , strain insulator consists of an assembly of suspension insulators as shown in Figure. The discs of strain insulators are used in the vertical plane. When the tension in lines is exceedingly high, at long river spans, two or more strings are used in parallel .

DIAGRAM FOR STRAIN INSULATOR

SHACKLE INSULATORS . In early days, the shackle insulators were used as strain insulators . But now a days, they are frequently used for low voltage distribution lines . Such insulators can be used either in a horizontal position or in a vertical position . They can be directly fixed to the pole with a bolt or to the cross arm.

DIAGRAM FOR SHACKLE INSULATOR

Potential distribution over suspension insulator string The voltage impressed on a string of suspension insulators does not distribute it self unformally across the individual discs due to the presence of shunt capacitance . The disc nearest to the conductor has maximum voltage across it .as we move towards the closs arm , the voltage across each disc goes on decreasing. The unit nearest to the conductor is under maximum electrical stress and it likely to the punctured . Therefore , means must be provided to equalise the potential across each unit. If the voltage impressed across the string were d.c.., then voltage across each unit would be the same. It is because insulator capacitances are ineffective for d.c.

DIAGRAM

DERIVATION Applying Kirchhoff’s current law to node A , we get, I 2 = I 1 + i 1 or V 2ω C * = V 1ω C + V 1ω C 1 or V 2ω C = V 1ω C + V 1ω K C ∴ V 2 = V 1 (1 + K ) ...( i ) Applying Kirchhoff’s current law to node B , we get, I 3 = I 2 + i 2 or V 3 ω C = V 2ω C + ( V 1 + V 2) ω C 1 †

or V 3 ω C = V 2ω C + ( V 1 + V 2) ω K C or V 3 = V 2 + ( V 1 + V 2) K = KV 1 + V 2 (1 + K ) = KV 1 + V 1 (1 + K ) 2 [ V 2 = V 1 (1 + K )] = V 1 [ K + (1 + K ) 2 ] ∴ V 3 = V 1[1 + 3 K + K 2] ...( ii ) Voltage between conductor and earth ( i.e., tower) is V = V 1 + V 2 + V 3 = V 1 + V 1(1 + K ) + V 1 (1 + 3 K + K 2) = V 1 (3 + 4 K + K 2 )

∴ V = V 1(1 + K ) (3 + K ) ...( iii ) From expressions ( i ), ( ii ) and ( iii ), we get, V 1/1= V2/1+K=V3/1+3K+ K 2 =V/(1+K)(3+K) ...( iv ) ∴Voltage across top unit, V 1 = V/ ( 1 + K )(3 + K )

Voltage across second unit from top, V 2 = V 1 (1 + K ) Voltage across third unit from top, V 3 = V 1 (1 + 3 K + K 2) %age String efficiency = Voltage across string×100/ n ×Voltage across disc nearest to conductor = V/ 3 × V3 ×100

METHODS OF IMPROVING STRING EFFICIENCY By using longer cross arms : The value of string efficiency depends up on the value of K.ratio of shunt capacitance to mutual capacitance. The lesser the value of k , the greater is the string efficiency and more uniform is the voltage distribution. 2. By grading the insulators: In this method , insulators of different dimensions are so chosen that each has a different capacitance. Since voltage is inversely proportional to capacitance. 3. By using a guard ring: The potential across each unit in a string can be equalised by using a guard ring which is a metal ring electrically connected to the conductor and surrounding the bottom insulator.

DIAGRAM FOR METHODS OF STRING EFFICIENCY

ONE MARKS : Define insulator Name types of insulator. Give any four reason for causes failure of insulator. Define string efficiency

12 MARKS Explain the various methods of testing of insulators Bring out the reasons for the failure of Insulator (6) Explain any two methods to improve the string efficiency (6)

THANK YOU
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