GOVERNMENT COLLEGE OF TEACHER EDUCATION THYCAUD Prepared By RANI J Mathematics Option
QUADRILATERAL AND TRIANGLE
TRANSFORMING QUADRILATERAL TO TRIANGLE A B C D
DRAW DIAGONAL BD A B C D
EXTEND AB AT ‘E’ AND JOIN DE WE GET TRIANGLE BED A B E D C AREA OF TRIANGLE ABD + AREA OF TRIANGLE BED = AREA OF QUADRILATERAL ABCD = AREA OF TRIANGLE AED
AREA OF QUADRILATERAL ABCD = AREA OF TRIANGLE ABD + AREA OF TRIANGLE BED ie ., AREA OF TRIANGLE AED
HOW CAN WE SAY TRIANGLE BCD IS SAME AS TRIANGLE BED
DRAW PARALLEL OF BD THROUGH C A B C D
A B C D IF WE MARK A POINT ‘ P’ ON THIS PARALLEL LINE, THEN BY JOINING PD AND PB, WE GET TRIANGLE BPD HAVING SAME AREA AS OF TRIANGLE BCD P
TRIANGLE BPD HAVE SAME AREA AS TRIANGLE BCD THEREFORE AREA OF QUADRILATERAL ABCD = AREA OF QUADRILATERAL ABPD
A B C D E Extend AB so that it meet on the parallel at ‘E’ Join ED we get Triangle BED which is equal to Triangle BPD and T riangle BCD Area of Quadrilateral ABCD is equal to Area of Triangle AED
Quadrilateral ABCD is transformed to triangle AED A E B D C