The Second Derivative Test is a powerful tool for understanding the behavior of a function around critical points . It leverages the second derivative of a function, denoted as f''(x) . Here's the key connection: What is the second derivative test? If f''(x) is positive at a critical point, it suggests that the function has a local minimum at that point If f''(x) is negative , it implies a local maximum And if f''(x) equals zero , the test is inconclusive, indicating a possible saddle point In essence, the Second Derivative Test tells you whether the function is bending upward (concave up) or downward (concave down) at a critical point
Let's put the Second Derivative Test to work with a real function. Consider this function: f(x) = x 3 - 6x 2 + 12x + 5 Our mission is to find the critical points and determine whether they represent local minima, maxima, or saddle points Applying the second derivative test
Step 1: find critical points Set f'(x) equal to zero and solve for x to find critical points 3x^2 - 12x + 12 = 0 Once you've solved for x, you'll have the critical points Begin by calculating the first and second derivatives of f(x) . The first derivative, f'(x), gives us critical points: f'(x) = 3x^2 - 12x + 12
Step 2: use the second derivative test Calculate f''(c) If f''(c) is positive , it indicates a local minimum at x=c If f''(c) is negative , it suggests a local maximum If f''(c) equals zero , the test is inconclusive, indicating a possible saddle point By applying this test to each critical point, you can determine the nature of the extrema
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