Solved Numericals on Water Analysis: EDTA Method, Clark Method, Lime-Soda Process and Zeolite Process

Numericals on Water Analysis: EDTA Method, Clark Method, Lime-Soda Process and Zeolite Process

1. Water Analysis
Calculate the permanent and temporary hardness in ppm of a water sample with the
given data……
1.50mL of distilled water = 0.5mL of soap solution
2.50mL of CaCl
2standard solution = 40.5mL of soap solution
3.50mL of given water = 15.5mL of soap solution
4.50mL of boiled water = 12.5mL of soap solution

2. Calculate the permanent and temporary hardness in ppm of a water sample with the
given data……
1.50mL of distilled water = 0.5mL of soap solution
2.50mL of CaCl
2standard solution = 40.5mL of soap solution
3.50mL of given water = 15.5mL of soap solution
4.50mL of boiled water = 12.5mL of soap solution
V
1mL
V
2mL
V
3mL
V
4mL
Total hardness =
V
3-V
1
V
2-V
1
X 1000 ppm

3. Permanent hardness =
V
4-V
1
V
2-V
1
X 1000 ppm
Temporary hardness = Total Hardness -Permanent Hardness
Now, put the values and find answers…..

4. Total Hardness = 375 ppm
Permanent Hardness = 300 ppm
Temporary Hardness = 75 ppm
Your answers are ready……

5. A standard hard water contains 15 gm of CaCO
3per liter, 20 mL of this required 25 mL
of EDTA solution, 100 mL of sample water required 18 mL of EDTA solution.
The sample after boiling required 12 mL EDTA solution.
Calculate the temporary hardness of the given sample of water, in terms of ppm.

8. 1. Standardization of EDTA solution
Given, 1 Liter of standard hard water contains 15 gm CaCO
3
1000 mL of standard hard water contains 15000 mg CaCO
3
1 mL of standard hard water contains 15 mg CaCO
3
Now, 25 mL of EDTA = 20 mL of standard hard water
= 20 x 15
= 300 mg of CaCO
3
1 mL of EDTA = 300/25 mg of CaCO
3equivalent hardness
= 12 mg of CaCO
3equivalent hardness

9. 2. Calculation of Total Hardness of water
100 mL of sample water = 18 mL of EDTA
= 18 x 12
= 216 mg of CaCO
3equivalent hardness
1000 mL of sample water = 2160 mg of CaCO
3equivalent hardness
1 Liter of sample water = 2160 mg of CaCO
3equivalent hardness
Hence, Total Hardness of Water = 2160 ppm

10. 3. Calculation of Permanent Hardness
100 mL of boiled water = 12 mL of EDTA
= 12 x 12
= 144 mg of CaCO
3equivalent hardness
1000 mL of sample water = 1440 mg of CaCO
3equivalent hardness
1 Liter of boiled water = 1440 mg of CaCO
3equivalent hardness
Hence, Permanent Hardness of Water = 1440 ppm

11. Temporary hardness = Total Hardness -Permanent Hardness
4. Calculation of Temporary Hardness
Total Hardness = 2160 ppm
Permanent Hardness = 1440 ppm
Temporary Hardness = ??? ppm

13. Lime Requirement
Soda Requirement

19. Solved Numerical
on
Zeolite Process