Special factor patterns

zagorskij 319 views 17 slides Jun 10, 2011
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1. Write as a Binomial:
(9-w)(9+w)
2. Write each square as a
trinomial:
(6c-1)²
3. Simplify:
(y+4)(y+10)

a²-b²  (a+b)(a-b)
(First #)² - (Second #)² =
(sum of 2 squares) x (their
difference)

Ex:
9a²-4b²=(3a+2b)(3a-2b)
3a is the square root of 9a² and
2b is the square root of 4b²

Ex:
36-25

81-16
***After you factor the number the first time, if there
still is an a²-b² in the subtraction binomial, you have
to factor again until there are no squares left.***

a²+(-)2ab+b²  (a+(-)b)²
If the middle number in the equation
equals twice the square root of a
times the square root of b, then you
can factor it.

Ex:
a²+2a+1= (a+1)²
a and 1 are the square roots of the first and
last numbers

Ex:
u²-6u+9

Ex:
b²+12b+4
This trinomial can’t be factored this way
because the middle number does not equal
twice the product of the first and last number.

Ex:
121c^4-264c²+144
^4 means to the fourth power****

x²+(-)bx+c  (x + factor of b
that adds to c) (x +(-) factor of b
that adds to c)

Ex:
x²+8x+15= (x+3) (x+5)
5 and 3 add up to 8, and
are a factor pair of 15.

Ex:
x²-10x+24

Ex:
y²+20yz+91z²

Ex:
x^4-15x²y²-16y^4
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