Structure and properties of ionic and covalent compounds.ppt

Structure and properties of ionic and covalent compounds

1. CHEM 120: Introduction to CHEM 120: Introduction to
Inorganic ChemistryInorganic Chemistry
Instructor: Upali Siriwardane (Ph.D., Ohio State
University)
CTH 311, Tele: 257-4941, e-mail:
[email protected]
Office hours: 10:00 to 12:00 Tu & Th ; 8:00-
9:00 and 11:00-12:00 M,W,& F

2. Chapters Covered and Test datesChapters Covered and Test dates
•Tests will be given in regular class periods  from  9:30-10:45 a.m. on
the following days:
September 22,     2004 (Test 1): Chapters 1 & 2
•October 6,         2004(Test 2):  Chapters  3, & 4
•October 20,         2004 (Test 3): Chapter  5 & 6
•November 3,        2004 (Test 4): Chapter  7 & 8
•November 15,      2004 (Test 5): Chapter  9 & 10
•November 17,      2004 MAKE-UP: Comprehensive test (Covers all
chapters
•Grading:
• [( Test 1 + Test 2 + Test3 + Test4 + Test5)] x.70 + [ Homework + quiz average] x 0.30 = Final Average
•                               5

3. Chapter 4: Structure and
properties of ionic and covalent
compounds
We now put atoms and ions together
to form compounds

4. Chapter 4. Structure and Properties
of Ionic and Covalent Compounds
1. Classify compounds as ionic, covalent, or polar covalent bonds.
2. Write the formulas of compounds when provided with the name of the
compound.
3. Name common inorganic compounds using standard conventions and
recognize the common names of frequently used substances.
4. Predict the differences in physical state, melting and boiling points,
solid-state structure, and solution chemistry that result from
differences in bonding.
5. Draw Lewis structures for covalent compounds and polyatomic ions.
6. Describe the relationship between stability and bond energy.
7. Predict the geometry of molecules and ions using the octet rule and
Lewis structure.
8. Understand the role that molecular geometry plays in determining the
solubility and melting and boiling points of compounds.
9. Use the principles of VSEPR theory and molecular geometry to
predict relative melting points, boiling points, and solubilities of
compounds.

5. Start learning the formulas and
the names and charges of the
ions found in table

6. •Why have we been so interested in where
the electrons are in an atom? And what is
the importance of valence electrons?
•Valence e’s are involved in_______--the no
of valence e’s has an important influence on
______ of bonds formed. The filled inner
core does not directly affect bond
formation.

7. Compound
•Bonds are formed by a transfer of ________
from one atom to another or by a ______
_________ between 2 atoms.

8. Lewis (dot) Symbols

9. Lewis (dot) symbols
•Introduced by G. N. Lewis
•Useful for representative (sp block) elements only
•Group no. = no of valence e-’s (no of dots)

10. Lewis symbols for A groups
•The elements’ symbol represents the inner
core of electrons. Put a dot for each valence
electron around the symbol.
•Remember that the no. of valence electrons
for the A groups is equal to ?
•Each unpaired electron may be used in bond
formation

11. Remember the octet rule from
chapter 3
•So the ions formed by the elements in:
•IA
•IIA
•IIIA
•VA
•VIA
•VIIIA

13. Ionic bonding
•Extra stability has been noted for the noble
gas configuration (8 e-s in valence shell)--
(for A elements)
•Ionic bonding
• Each atom in the ionic bond

14. •Ionic compounds are formed between
•And
•When forming an ionic bond each atom in
the bond attains a noble gas configuration
by a “complete” transfer of

15. •An ionic bond is the electrostatic force that
holds ions together in an ionic compound
•An ionic bond is a very strong bond; ionic
cmpds have high m and b pts.

16. Typical ionic reactions with
Lewis structures
+
-
Na + F Na F

17. What about Li and S?
+ 2-
Li +S 2 Li S2

18. What about Ca and O
•Formula is

19. What about Ca and N?
•Formula is

20. Covalent bonding
•Not all bonds are ionic.
•________ bonds are bonds in which two (or
more) electrons are ______ by two atoms.
•One shared electron pair is

22. •A reminder:
•Only valence electrons are involved in
bonding. Group No. = # valence e-s for A
elements.
•Covalent bonds are formed
•Each atom in bond attains noble gas
configuration by sharing of e- pairs (H
2
bond only has 2 e-’s)

23. Covalent bond formation
•Look at formation of H
2 molecule.
• H
.
+
.
H ----> H:H (H-H)
1s
1
1s
1
bond formed by overlap
of 1s orbitals

24. What about F
2
or Cl
2
?

25. ____ _____ - pairs of valence electrons not
involved in covalent bond formation
Lewis structure - representation of covalent
bonding in which lone pairs are shown as
pairs of dots and bonding pairs are (usually)
shown as lines
Cl Cl2 Cl ClClor
Lone
pairs
Bonding
pairs
Usual
representation

26. Polar covalent bonding and
electronegativity
•Not all covalent bonds are formed btn the
same 2 atoms (as H
2, homonuclear
diatomic: _______sharing of e-’s in bond)

27. Polar covalent bonds
•What about the bond in H-F?
•It is known that F is more likely to attract
e-’s to itself than H, leading to an unequal
sharing of the e- pair.
•The covalent bond in which there is unequal
sharing:

28. H F FH
Polar covalent bond or polar bond is a covalent bond
with greater electron density around one of the two
atoms
electron rich
region
electron poor
region
e
-
riche
-
poor

+

-
9.5

29. HCl
ClCl
+
-
Na Cl
Continuum of bond polarity
•(Nearly) complete e
-
transfer = ionic
bond
•Unequal sharing of e- pair = polar
covalent bond.
e-s are polarized toward Cl
•Equal sharing of e- pair = nonpolar
covalent bond

30. Electronegativity
•Electronegativity:
•.
•Eneg is a relative concept. Elements with

31. Lanthanides 1.1-1,3
Actinides 1.3-1.5

32. Electronegativity differences
•0.2 - 0.5 will be a ________________ bond
•0.5 - 1.6 will be a ________________ bond
•> 1.6 will be a ________________ bond

33. Electronegativity differences
•In general the _______ the difference in
eneg btn the 2 atoms in the bond, the ____
______ the bond.
•If the difference is zero,
bond (equal sharing of electron pair(s)
(H
2
, Cl
2
, O
2
, F
2
, N
2
)

34. •If the difference is >0 and <1.9, have a
:
HCl (3.0 - 2.1); HF (4.0-2.1);
OH (3.5-2.1)
•If the difference is > 1.9, have
NaCl (3.0-0.9); CaO (3.5-
1.0)

35. Classify as ionic or covalent
•NaCl
•CO
•ICl
•
H
2

36. •Which bond is the most polar (most ionic),
which the least polar (most covalent)?
•Li-F Be-F B-F C-F N-F O-F F-
F

37. • Classify the following bonds as ionic,
polar covalent, or covalent.
A) the CC bond in
H
3
CCH
3
•B) the KI bond in KI
•C) the NB bond in H
3NBCl
3
•D) the CF bond in CF
4

38. Chemical formulas
•Express composition of molecules (smallest
unit of covalent cmpds) and ionic
compounds in chemical symbols
–H
2O, NaCl

39. Writing formulas for ionic cmpds
•Compounds are neutral overall. Therefore
–NaCl is array of Na
+
and Cl
-
ions
–
Na
2S is array of Na
+
and S
2-
ions

40. Predict the formulas for the cmpd
formed btn
•Potassium and chlorine
•Magnesium and bromine
•Magnesium and nitrogen

42. Symbol Name SymbolName
H
+
Hydrogen ionH
-
Hydride ion
Li
+
Lithium ion F
-
Fluoride ion
Na
+
Sodium ion Cl
-
Chloride ion
K
+
Potassium ionBr
-
Bromide ion
Be
2+
Beryllium ionI
-
Iodide ion
Mg
2+
Magnesium
ion O
2-
Oxide ion
Ca
2+
calcium ion S
2-
Sulfide ion
Ba
2+
barium ion N
3-
Nitride ion
Zn
2+
zinc ion P
3-
Phosphide ion

43. Formula Name Formula Name
NO
3
-
nitrate CO
3
2-
carbonate
NO
2
-
nitrite SO
4
2-
sulfate
CN
-
cyanide SO
3
2-
sulfite
MnO
4
-
permanganate PO
4
3-
phosphate
OH
-
hydroxide PO
3
3-
phosphite
O
2
2-
peroxide ClO
4
-
perchlorate
HCO
3
-
hydrogen carbonate ClO
3
-
chlorate
HSO
4
-
hydrogen sulfate ClO
2
-
chlorite
HSO
3
-
hydrogen sulfite ClO
-
hypochlorite
HPO
4
2-
hydrogen phosphate CrO
4
2-
chromate
H
2
PO
4
-
dihydrogen phosphate C
2
H
3
O
-
2 acetate

44. Symbol (Stock system)Common Symbol (Stock system)Common
Cu
+
copper(I) cuprous Hg
2
2+
mercury(I)mercurous
Cu
2+
copper(II) cupric Hg
2+
mercury(II)mercuric
Fe
2+
iron(II) ferrous Pb
2+
lead(II) plumbous
Fe
3+
iron(III) ferric Pb
4+
lead(IV) plumbic
Sn
2+
tin(II) stannous Co
2+
cobalt(II)cobaltous
Sn
4+
tin(IV) stannic Co
3+
cobalt(III)cobaltic
Cr
2+
chromium(II)chromous Ni
2+
nickel(II)nickelous
Cr
3+
chromium(III)chromic Ni
4+
nickel(IV)nickelic
Mn
2+
manganese(II)manganous Au
+
gold(I) aurous
Mn
3+
manganese(III)manganic Au
3+
gold(III) auric

45. Polyatomic ions Table
•Just have to memorize
•NH
4
+
ammonium ion
•CO
3
2-
carbonate ion
•CN
-
cyanide ion
•HCO
3
-
hydrogen (or bi) carbonate ion
•OH
-
hydroxide

46. •NO
3
-
nitrate ion
•NO
2
-
nitrite ion
•PO
4
3-
phosphate ion
•SO
4
2-
sulfate ion
•HSO
4
-
hydrogen sulfate ion
•SO
3
2-
sulfite ion
•CH
3
COO
-
(C
2
H
3
O
2
-
) acetate ion

47. •These polyatomic ions also form ionic
cmpds when they are reacted with a metal
or a nonmetal in the case of the ammonium
ion (or with each other as ammonium
sulfate). These polyatomic species act as a

48. •So the formula for the cmpd formed btn the
ammonium ion and sulfur would be:
•
•
•and between calcium and the phosphate ion:
•

49. •Ionic cmpds do not exist in discrete pairs of
ions. Instead, in the solid state, they exist as
a three dimensional array--crystal lattice --
of cations and anions--are neutral overall,

50. Given name, write formula
•potassium oxide
•magnesium acetate

51. Naming ionic cmpds
•Name the cation and anion but drop the
word ion from both. This includes the
polyatomic ions.
•
Na
2S
•
Ca
3N
2

52. Name
•Na
3PO
4
•NH
4
Cl
•K
2S

53. Cations with more than one
charge
•Cu
+
copper(I); Cu
2+
copper(II)
•So Cu
2O is
and
•CuO is

54. Given name, write formula
•Ammonium chloride
•potassium cyanide
• silver oxide
•Magnesium chloride
•Sodium sulfate
•Iron(II) chloride

55. To name covalent cmpds
•Name the parts as for ionic cmpds (CO:
carbon and oxide) but tell how many of
each kind of atom by use of Greek prefixies.
(Table 4.4)
•The mono- (for 1) may be omitted for the
first element

56. •Prefix meaning
•Mono- 1
•Di- 2
•Tri- 3
•Tetra- 4
•Penta- 5
•Hexa- 6
•Hepta- 7
•Octa- 8
•Nona- 9
•Deca- 10

57. •CO
•
•
CO
2

•
P
4S
10
•
•Boron trichloride
•
Water H
2O Ammonia NH
3

58. Write formula
•Diboron trichloride
•Sulfur trioxide
•Potassium sulfide

59. Covalent cmpds
•Remember covalent cmpds--
•A _________ is the smallest unit of a covalent
cmpd that retains the characteristics of the cmpd.
Molecule - two or more atoms in a definite
arrangement held together by chemical bonds.
(H
2
O, Cl
2
) [Cl
2
is considered a molecule but not a
cmpd]
•Molecular cmpds exist as

60. Comparison of properties of ionic
and covalent cmpds
•Physical state:
• Ionic cmpds are
• Molecular cmpds can be

61. Comparison continued
•Melting (___________) and
boiling (_________) pts
•In general the melting and boiling temps are
much _______for ionic cmpds than for
molecular (covalent) cmpds. The ionic bond
is very strong and requires a lot of (heat)
energy to break the bond. The bond btn
molecular species is not as strong.

62. Comparison continued
•Structure in solid state:
•Ionic solids--
•Covalent solids--

63. Comparison continued
•In aqueous (H
2O) solution:
•Ionic cmpds dissociate into the
•Many covalent cmpds when dissolved in
water retain their structure and molecular
identity

64. •Learn the names, formulas, charges, etc for
those ions highlighted in table 4.3.
•HCO
3
-
: you should learn as bicarbonate

65. Writing Lewis structures for
covalent species
•These rules are for covalently bonded cmpds
only (btn 2 or more nonmetals)
•Do not use them for ionic cmpds.
•1. Count the total no. of valence electrons (the
group no. is equal to the no. of valence
electrons).
•if the species is an anion, increase the no. of
valence electrons by the charge on the ion

66. •if the species is a cation, subtract the charge
of the cation from the total no. of valence
electrons.
•2.Count the total no. of atoms, excluding H,
in the molecule or ion. Multiply that no. by 8.
•Exception: multiply the no. of H’s by 2.
•This tells you how many electrons you would
need if you were putting 8 electrons around
all atoms without any sharing of electrons
(and 2 around all H’s).

67. •3. Subtract the no. of e-’s calculated in step 1
from the no. in step 2. This gives you the no.
of e-’s that must be shared to get an octet
around all atoms in the molecule.
•4. no. of e-’s that must be shared /2 gives you
the no. of bonds.
•5. subtract the no. of e-’s that are shared (from
step 3) from the total no. of valence e-’s. This
gives you the no. of unshared e-’s.
•If you divide the no. of unshared e-’s by 2 you
get the no. of lone pairs.

68. •Write the skeletal structure and fill in with
the info you came up with. After you’ve put
in the # bonds calculated, fill in the octets.
•H (and F) form only one bond. Therefore
they can only be terminal atoms in a
structure.
•So you can not have
• C---H---C
•It has to be H---C--C

69. •Examples
•CH
4
•PCl
3
•SO
3
2-
•NO
3
-
•CN
-
•COBr
2 (C is bonded to O and Br atoms)
•SO
2
•H
3O
+
(hydronium ion
•N
3
-

70. Draw Lewis structure of CO
2
i) Valence electrons: 4 + 2 x 6 = 16 ( 8 pairs)
ii) Central atom C; O -- C -- O
iii) Give octet to carbon
--
O -- C -- O
--
Try to fill octet to O
iv) Count electrons:
4 bond pairs = 4 pairs
4 lone pairs = 4 pairs
8 electron pairs

71. Multiple bonds
•In general a triple bond (N
2) is ________
than a double bond (O
2) which is
________than a single bond (F
2).
•Bond order: BO of 1--single bond, BO of
2-- -double bond, BO of 3 --triple bond.
•The stronger the bond,

72. Terminology used in describing Lewis structures of molecules
Bond pairs: An electron pair shared by two atoms in a bond.
Lone pair: An electron pair found solely on a single atom.
Single covalent bond -
Bond between two atoms when they shared 1 pair
Double covalent bond –
Bond between two atoms when they shared 2 pairs.
Triple covalent bond –
Bond between two atoms when they shared 3 pairs.
Lewis Structure, Stability, Multiple Bonds, and Bond Energies
Bond order
The stability of a covalent compound is related to the bond energy.
The magnitude of the bond energy increases and the bond length
decreases in the order: single bond > double bond > triple bond.
Bond Energy order: single < double < triple
Bond length order: single (1) < double (2) < triple (3)

73. Resonance
•Resonance structure –1 of 2 or more Lewis
structures for a molecule (ion) that can’t be
represented with a single structure
•Resonance – use of

75. •Each resonance structure contributes to the
actual structure
–no single structure is a complete description
–positions of atoms must be the same in each,
only electrons are moved around
–actual structure is an “average”

76. •Draw resonance structures for SO
3
and N
3
-
.

77. Exceptions to Octet Rule
There are three classes of exceptions to the octet rule.
 
1) Molecules with an odd number of electrons;
2) Molecules in which one atom has less than an octet;
3) Molecules in which one atom has more than an
octet.

78. Let’s do Lewis structures for
•CO
2 (CS
2)
•O
3 (SO
2)
•I
3
-

79. 3D structure of species
•Electrostatic forces in ionic bonds is
_____________. But species with covalent
bonds have electron pairs concentrated btn
2 atoms and is ..
•We use VESPR theory to predict the shape
of the covalently bound species.

80. VSEPR theory

81. VSEPR
•Most stable geometry is one in which
electron pairs (electron clouds) are as

82. Shapes of molecules (3D)
•The geometry is determined by the atoms present
in the species. See atoms that are bonded to other
atoms. Don’t “see” lone pairs but they influence
geometry
•I. Diatomics (2 atoms only): always ________
•H
2, HCl, CO X----X

83. •II. Polyatomic (3 or more atoms) species:
Use VSEPR model to predict
shapes

84. Steps in applying VSEPR
•1. Do Lewis structure
•2. Count total e- pairs (clouds) around
central atom (A). Multiple bonds count as
one electron pair (cloud). In reality multiple
bonds are bigger than single bonds (electron
clouds larger).

85. •3. Separate e- pairs into bonded pairs (B)
and lone pairs (E)
•4. Apply table that I give you.
•5. Remember that lone pairs of e-’s are
invisible, but their presence affects the
final molecular geometry!!!!!
•Lone e- pair-lone e-pairs are more repulsive
than bonded pair-lone pair repulsions or
bonded pair-bonded pair repulsions.

86. VSEPR: valence shell electron pair
repulsion
•2 electron clouds around a central atom (A)

87. 2 electron clouds

88. Three electron clouds

89. Three electron clouds

90. Four electron clouds

91. Table 4.5 (changed)
•# e # bonded #lone pairs geom angle
clouds pairs pairs
•2
•3
•3
•4
•4
•4

92. Predict geometry
•H
2S
•SO
2
•CO
2
•CF
4
•H
2
CO
•ClO
3
-
•ClO
2
-

93. Polar vs nonpolar cmpds
•A molecule is polar if its centers of positive and
negative charges do not coincide. If a molecule is
polar we say that it acts as a dipole. In an electric
field nonpolar molecules (positive and negative
centers coincide) do not align with the field but
polar molecules do.
•Next we will see why this happens and the
implications.

94. Molecules are subjected to electric field
Polar molecules align with field
Nonpolar molecules are not affected

95. Polar molecules
•I. Diatomics, A-B
• a.If A = B have homonuclear diatomic;
has
•b. A ≠ B have heteronuclear diatomic

96. II. Polyatomic species are more complicated.
•Let’s look at VSEPR cases considered.
•General rule (my rule):

97. Which of these are polar?
•H
2S
•SO
2
•CO
2
•CF
4
•AlCl
3
•CHCl
3
•SCl
2

98. Properties based on electronic
structure and molecular geometry
•Intramolecular forces: within a molecule--
bonds
•Intermolecular forces: between molecules--
these determine important properties as
melting and boiling points and solubility

99. Solubility
•Like dissolves like:
• Polar cmpds dissolve in polar solvents
as ionic and polar cmpds (HCl)
in water
•Nonpolar cmpds dissolve in nonpolar
solvents: oils in CCl
4

100. Melting and boiling points
•Stronger the intermolecular forces the
higher the melting and boiling points
•In general for cmpds of similar weight:
polar moleculaes have stonger forces than
nonpolar cmpds
•In general for similar structure the greater
the mass the stronger the forces

101. Which have higher melting
(boiling pts)
•CO and NO
•F
2 and Br
2
•CH
3CH
2OH and CH
3CH
3