Let’s say you're measuring the flow in a stream, and you’ve divided the cross-section into smaller
segments. Here are the measurements:
Width of the stream = 10 meters
Depth at 5 points across the width: 0.5 m, 1 m, 1.5 m, 1 m, 0.5 m
Velocity at each point: 0.3 m/s, 0.5 m/s, 0.7 m/s, 0.5 m/s, 0.3 m/s
We need to calculate the streamflow.
Steps:
1.Calculate the Cross-sectional Area (A):
oFirst, calculate the area of each section by multiplying the width of each segment by the
average depth for that segment. In this case, we will use the average of adjacent points.
Segment Areas:
oArea=0.5 m×0.5 m=0.25 m2\text{Area} = 0.5 \, \text{m} \times 0.5 \, \text{m} = 0.25 \, \
text{m}^2
oArea=1.0 m×1.0 m=1.0 m2\text{Area} = 1.0 \, \text{m} \times 1.0 \, \text{m} = 1.0 \, \
text{m}^2
oArea=1.5 m×1.5 m=2.25 m2\text{Area} = 1.5 \, \text{m} \times 1.5 \, \text{m} = 2.25 \, \
text{m}^2
oArea=1.0 m×1.0 m=1.0 m2\text{Area} = 1.0 \, \text{m} \times 1.0 \, \text{m} = 1.0 \, \
text{m}^2
oArea=0.5 m×0.5 m=0.25 m2\text{Area} = 0.5 \, \text{m} \times 0.5 \, \text{m} = 0.25 \, \
text{m}^2
Total Area (A):
A=0.25+1.0+2.25+1.0+0.25=4.75 m2A = 0.25 + 1.0 + 2.25 + 1.0 + 0.25 = 4.75 \, \text{m}^2
2.Calculate the Average Velocity (V): Average velocity can be calculated by averaging the velocities
at the five points.
V=0.3+0.5+0.7+0.5+0.35=0.46 m/sV = \frac{0.3 + 0.5 + 0.7 + 0.5 + 0.3}{5} = 0.46 \, \text{m/s}
3.Calculate the Streamflow (Q):
Q=A×V=4.75 m2×0.46 m/s=2.19 m3/sQ = A \times V = 4.75 \, \text{m}^2 \times 0.46 \, \text{m/s} =
2.19 \, \text{m}^3/\text{s}
So, the streamflow is 2.19 m³/s.
3. Hydraulic Methods (Manning’s Equation)