Theorem: Angles opposite to equal sides of an isosceles triangle are equal.

Part 2: Theorem: Angles opposite to equal sides of an isosceles triangle are equal.

1. WE ARE ADDICTED TO LEARN

2. School of education Integrated B.Sc. - B.Ed. Name : Ramesh

3. Theorem : Angles opposite to equal sides of an isosceles triangle are equal.

4. A C B TO PROVE : ∠ABC = ∠ACB Theorem : Angles opposite to equal sides of an isosceles triangle are equal.

5. A C B D TO PROVE : ∠ABC = ∠ACB GIVEN : AB = AC Theorem : Angles opposite to equal sides of an isosceles triangle are equal.

6. A C B D TO PROVE : ∠ABC = ∠ACB GIVEN : AB = AC PROOF : Let us take a line AD bisecting angle ∠A Theorem : Angles opposite to equal sides of an isosceles triangle are equal.

7. A C B D TO PROVE : ∠ABC = ∠ACB GIVEN : AB = AC PROOF : Let us take a line AD bisecting angle ∠A so, ∠BAD = ∠CAD Theorem : Angles opposite to equal sides of an isosceles triangle are equal.

8. A C B D TO PROVE : ∠ABC = ∠ACB GIVEN : AB = AC PROOF : Let us take a line AD bisecting angle ∠A so, ∠BAD = ∠CAD AB = AC (given) Theorem : Angles opposite to equal sides of an isosceles triangle are equal.

9. A C B D TO PROVE : ∠ABC = ∠ACB GIVEN : AB = AC PROOF : Let us take a line AD bisecting angle ∠A so, ∠BAD = ∠CAD AB = AC (given) AD (common in ∆ABD and ∆ACD) Theorem : Angles opposite to equal sides of an isosceles triangle are equal.

10. A C B D TO PROVE : ∠ABC = ∠ACB GIVEN : AB = AC PROOF : Let us take a line AD bisecting angle ∠A so, ∠BAD = ∠CAD AB = AC (given) AD (common in ∆ABD and ∆ACD) ∴ ∆ABD ≅ ∆ACD ( By SAS congruence rule) Theorem : Angles opposite to equal sides of an isosceles triangle are equal.

11. A C B D TO PROVE : ∠ABC = ∠ACB GIVEN : AB = AC PROOF : Let us take a line AD bisecting angle ∠A so, ∠BAD = ∠CAD AB = AC (given) AD (common in ∆ABD and ∆ACD) ∴ ∆ABD ≅ ∆ACD ( By SAS congruence rule) ∴ ∠ABD = ∠ACD ( C.P.C.T. ) Theorem : Angles opposite to equal sides of an isosceles triangle are equal.

12. A C B D TO PROVE : ∠ABC = ∠ACB GIVEN : AB = AC PROOF : Let us take a line AD bisecting angle ∠A so, ∠BAD = ∠CAD AB = AC (given) AD (common in ∆ABD and ∆ACD) ∴ ∆ABD ≅ ∆ACD ( By SAS congruence rule) ∴ ∠ABD = ∠ACD ( C.P.C.T. ) or, ∠ABC = ∠ACB hence proved Theorem : Angles opposite to equal sides of an isosceles triangle are equal.

13. Thank you