90 180 270 360
1
0
-1
Y = sin x
540450
Period of graph is 360
0
Cycle starts again
Also applies to Y = cos x
Between 0
0
and 360
0
there is 1 cycle
Taking it Further
90 180 270 360
1
0
-1
Y = sin 2x
Period of graph is 180
0
There are 2 cycles between 0
0
and 360
0
Combining these rules
Draw y = 6sin2x
Max 6
Min -6
2 cycles
Period = 360 ÷ 2 = 180
0
90 180 270 360
6
0
-6
Y = 6sin 2x
Recognising Graph
Max 8
Min -8
4 cycles
90 180 270 360
8
0
-8
Y = 8cos4x
Cosine
Changing the Scale
Nice for Drawing Graphs
y = 4 Sin 6x
Cycles?
Period
6
360 ÷ 6 = 60
0
15 30 45 60
4
0
-4
30
0
60
0
90
0
120
0
7
0
-7
Not so nice for recognising graphs
Period = 120
0
No of Cycles in 360?360 ÷ 120 = 3
y = 7 cos 3x
240
0
360
0
Find equation of graph below.
Cycles
Max 7
Negative sin
360 ÷ 60 = 6
15 30 45 60
7
0
-7
y = -7sin6x
Remember rules for y = (x – 3 )
2
+ 5
Same rules for trig graphs!
3 units to right Up 5
Extra Trig Graph Rules
90 180 270 360
4
0
-4
Y = 4cos (x – 45
0
)
450
Y = 4cosx
45
0
to right
Sketch Normal Graph
Move each point
right/left
y =4cos(x – 45
0
)
90 180 270 360
11
0
-11
Recognising
Sin Graph
30
0
to right
y = 11 sin(x – 30
0
)
30
0
90 180 270 360
13
0
-13
Recognising
Cos Graph
20
0
to left
y = 13 cos(x + 20
0
)
-20
0
90 180 270 360
11
0
-11
A Bit of Confusion
Sin Graph
30
0
to left
y = 11 sin(x + 30
0
)
-30
0
60
0
Cos Graph
60
0
to right
y = 11 cos(x – 60
0
)
Both correct