VLP AND WORKING CHART LECTURE #2.pdf

VLP AND WORKING CHART LECTURE #2.pdf

1. Dr. MOHAMMED ABDUL AMEER ALHUMAIRI
MISAN UNIVERSITY
COLLEGE OF ENGINEERING –PETROLEUM DEPARTMENT
VFP
[email protected]

2. VERTICAL LIFT RELATIONSHIP
VFP

3. WORKINGCHARTSFORTUBINGSIZE1INCHANDDIFFERENTFLOWRATES

5. EXAMPLE:GIVENDATAARE,FLOWRATE=500BBL/DAY,
TUBINGSIZE=1.5INCH,THEPRODUCTIONALLOIL,GLR=200
SCF/BBL,WELLDEPTH5000FT,PTH=200PSI.
CALCULATEPWFFROMTHEABOVEGIVENDATA.
SOLUTION:
1-CHOOSETHEWORKINGCHARTFORQO=500BBL/DAYAND
TUBINGSIZE=1.5INCH.
2-INTERTHECHARTWITHTHEVALUEOFPTH=200PSIFROMX-
AXIS.
3-USETHEGLR=200SCF/BBLCURVETOFINDTHEEQUIVELENT
DEPTHFORPTHONY-AXIS.
4-THEEQUIVELENTDEPTHFORPTH=1300FT.
5-FINDTHEEQUIVELENTDEPTHFOR
PWF=EQUVELENTDEPTHFORPTH+WELLDEPTH
=1300+5000=6300FT.
6-USETHESAMEGLR=200SCF/BBLTOFINDTHEVALUEOF
PWF=1600PSI
PTH PWF

6. VerticalWorkingCharts:aredefinedasgraphicalpresentationofmultiphasecorrelation
(verticalandhorizontalflow),thatwereconstructedasrelationshipbetweenpressure
anddepthfordifferentflowrates,pipessize,GLRgasliquidratio
Pressure
depth
Flow rate
Pipe size
GLR

7. Wehaveverticalandhorizontalworkingchart,thesechartbuilddependonoilAPIgravity
andgasspecificgravityandaverageflowingtemperature,throughthesecharts,wecan
constructingverticalflowperformancewithIPR.
ThecrosspointbetweenIPRandverticalflowperformance(VFP)representtheallowable
flowrate.
Cross point

8. Exampledepth=6000ft,tubingsize=2inch,Pr=3000psi,GLR=400scf/bbl,Pth=200Psi,
(wellheadpressure),Qo=400bbl/day(alloil).
DeterminePwffromworkingchart.
Solution:
Pth=120psi
EquivalentdepthtoPth=2200psi.
Equivalentdepthtopwf=2200+6000=8200ft
Pwf=1230Psi
NowfindPthfromPwf=1230psi
Solution:
EquivalentdepthtoPwf=8200ft
EquivalentdepthtoPth=8200-6000=2200ft
SoPthfromworkingcharts=120Psi

11. Pth=200 psi
Equivalent depth to
Pth=2200 ft
Equivalent depth to Pwf
=2200+ 6000=8200 ft
Pwf=1230
psi

12. Tubing in fig(1) greater than tubing in fig(2)
Heriot Watt
Fig 1 Fig 2 Fig 3

13. Example
Pr=2000Psi,PI=1.5bbl/day/psi,qo=400bbl/day,alloil,depth=6000ft,GLR=400scf/bbl,Pth=200Psitubing
size=2inch.
Solution:
FindPwffromPr=2000psi,qo=400bbl/day,PI=1.5bbl/day/psi
????????????=
��
��−�????????????
=1.5=
400
2000−�????????????
===�????????????=1733��??????
NowIPRcanbeconstructedfromPrand(pwf,qo),(twotestpoints)
Toconstructtheverticalflowperformanceneedtoassumeqo(availablefromworkingcharts)tofindpwf
dependingonPth,asfollows:
Fromworkingchartsfortubingsize2incheswehavedifferentflowrate(200,400,600,800,1000,1500),from
thesechartsfindPwfforeachflowrate:
Flow rate (
available )
Pwf(from working charts for Pth=120psi)
200 1100
400 1300
600 1380
800 1450
1000 1570
1500 1800
Pwfqo
20000
1733400
10001500

14. IPR
VFP
Qo= 820
bbl/day
Pwf=1450 Psi

15. Example
Depth8000ft,Pr=2000psi,PI=2bbl/day/psi,assumelinear,Pth=120psi,tubingdiameter2.5inch,GLR=600
scf/bblDeterminetheflowrate,assumealloil.
Solution:
ConstructIPR
AssumeanyvalueforPwf=1000psilessthanPr.
????????????=
��
��−�????????????
=2=
��
2000−1000
��=2000��??????/??????�??????
NowconstructverticalflowcurveforPth=120psi,byassumingqoavailablefortubingsize=2.5inch:
FromtheverticalflowcurveandIPR:
Qo=1150bbl/day
Pwf=1410psi
Flow rate ( available )Pwf(from working charts for Pth=120psi)
400 950
800 1255
1000 1360
1200 1440
1500 1570
Pwfqo
20000
10002000