Learning Competency Graphs and illustrates a linear function and its : (a) domain (b) r ange (c) table of values; (d) intercepts; and (e) slope 2
Linear Function 3 A linear function is a function that can be written in the form π π = ππ + π β where π and π are real numbers β where π tells us the slope of a line and π tells us where the graph crosses the π¦ - axis.
Linear Function 4 π π = ππ + π A linear function is a function whose graph is a straight line. Its equation can be written in the form π = ππ + π , where π₯ and π¦ are used for the independent and dependent variables, respectively, π β .
Linear Function 5 π = π π π π = ππ + π π = ππ + π β π(π₯) means βthe value of π at π₯ β π(π) or π(π) β letters other than π such as πΊ and π» , or π and β can also be used.
6 Linear Function as an Equation Which of the following function is linear? π = ππ + π π π = ππ + π 1. π¦ = 8π₯ β 5 2. π¦ = β π₯ 3 + 2 3. π¦ = π₯ π₯ 4. π¦ = 2 + 7 5. π¦ = π₯ 2 β 3 Linear Function. It is in the form π¦ = ππ₯ + π , where π = 8 and π = β5 Linear Function. By rewriting the equation, we can have π¦ = 1 1 3 3 β π₯ + 2 where π = β and π = 2 . Linear Function. By rewriting the equation, we can have π¦ = π₯ + where π = 1 and π = . Not a Linear Function. It cannot be expressed in the form π¦ = ππ₯ + π because π₯ is in the denominator. Not a Linear Function. The degree of the equation is on the second degree.
A linear function can also be described using its graph . Letβs determine the values of the function π if π π₯ = 2x + 1 at π₯ = β 2, β1, 0, 1, and 2 , and see if it will illustrate a straight line. SOLUTION: = 2π₯ + 1 = 2 β2 + 1 1. π π₯ π β2 π β2 π βπ = β4 + 1 = βπ π π(π) βπ βπ Ordered pair: (βπ, βπ) REMEMBER: Note that an ordered pair (π₯, π¦) can be written as (π₯, π π₯ ) for any function in π π₯ notation. 7
A linear function can also be described using its graph . Letβs determine the values of the function π if π π₯ = 2x + 1 at π₯ = β 2, β1, 0, 1, and 2 , and see if it will illustrate a straight line. SOLUTION: = 2π₯ + 1 = 2 β1 + 1 2. π π₯ π β1 π β1 π βπ 8 = β2 + 1 = βπ Ordered pair: (βπ, βπ) π π(π) βπ βπ βπ βπ
A linear function can also be described using its graph . Letβs determine the values of the function π if π π₯ = 2x + 1 at π₯ = β 2, β1, 0, 1, and 2 , and see if it will illustrate a straight line. SOLUTION: 3. π π₯ = 2π₯ + 1 π = 2 + 1 π = 0 + 1 π π = π Ordered pair: (π, π) 9 π π(π) βπ βπ βπ βπ π π
A linear function can also be described using its graph . Letβs determine the values of the function π if π π₯ = 2x + 1 at π₯ = β 2, β1, 0, 1, and 2 , and see if it will illustrate a straight line. SOLUTION: 4. π π₯ = 2π₯ + 1 π 1 = 2 1 + 1 π 1 = 2 + 1 π π = π Ordered pair: (π, π) 10 π π(π) βπ βπ βπ βπ π π π π
A linear function can also be described using its graph . Letβs determine the values of the function π if π π₯ = 2x + 1 at π₯ = β 2, β1, 0, 1, and 2 , and see if it will illustrate a straight line. SOLUTION: 5. π π₯ = 2π₯ + 1 π 2 = 2 2 + 1 π 2 = 4 + 1 π π = π Ordered pair: (π, π) 11 π π(π) βπ βπ βπ βπ π π π π π π
A linear function can also be described using its graph . Letβs determine the values of the function π if π π₯ = 2x + 1 at π₯ = β2, β1, 0, 1, and 2 , and see if it will illustrate a straight line. π π(π) βπ βπ βπ βπ π π π π π π 12
13 A linear function can also be illustrated using a table of values . π βπ βπ π π π π(π) β3 β1 1 3 5 We can do this by looking at the first difference of the π₯ - coordinates and π¦ - coordinates. +π +π +π +π +π +π +π +π Since both quantities change by constant amounts, this means that the relationship between the quantities is linear .
A linear function can also be illustrated using a table of values . π π π π π π π(π) 3 6 9 12 15 +π +π +π +π +π 14 +π +π +π Since the π₯ -coordinates and the π¦ - coordinates increase by constant amounts, this table of values illustrates a linear function .
A linear function can also be illustrated using a table of values . π βπ βπ βπ π π π(π) 2 3 5 8 12 +π +π +π +π +π 15 +π +π +π Since the π₯ -coordinates and the π¦ -coordinates do not increase by constant amounts, this table of values does not illustrate a linear function .
A linear function can also be illustrated using a table of values . π π ππ ππ ππ ππ π(π) 25 50 75 100 125 +π +π +π +π +ππ 16 +ππ +ππ +ππ Since the π₯ -coordinates and the π¦ - coordinates increase by constant amounts, this table of values illustrates a linear function .