Alternating Current Lecture Introduction

Alternating Current Lecture Introduction

1. Alternating Current
Class -12th
PRIYANKA JAKHAR
PHYSICS LECTURER
GGIC VIJAY NAGAR
GHAZIABAD

2. Alternating Current--Alternating current(AC)electricityisthe type of electricity
commonly used in homesandbusinessesthroughoutthe world.
Whiledirect current(DC) electricityflowsin onedirectionthrough a wire.
ACelectricityalternatesits direction inaback-and-forthmotion.
•Alternating current is defined as the current that varies like a sine function with time.
•The value of current will oscillate between a maximum value and a minimum value.
•In caseofACthe current ischangingitsmagnitude at every instant of time.
•The direction of current will be clockwise and anticlockwise and it will keep on repeating.
ASymbol:
C
created by an electroniccircuitry, allowing for a wide range of applications

3. An electric current whose magnitude changes continuously with time and changes its direction periodically,
is called an alternating current.
The instantaneous value of alternating current at any instant of time t is given by
I =I
msin ωt
Where I
m= maximum or peak value of the AC .
•Alternating voltage is expressed as: -V = V
msinωt
•Where V
m= peak value of the voltage.
•Advantages of AC
1)Easily stepped up or stepped down using transformer
2)Can be regulated using choke coil without loss of energy
3)Easily converted in to dc using rectifier (Pn-diode)
4)Can be transmitted over distant places
5)Production of ac is more economical
created by an AC electric generator,whichdetermines thefrequency
the voltage can be readily changed, thus making it more suitableforlong-distance
transmissionthanDCelectricity
can employ capacitors and inductorsinelectroniccircuitry, allowing for a wide range of
applications
E, I–Instantaneous value ofemf
andcurrent
E
0, I
0–Peak or maximum value or
amplitude ofemfandcurrent
ω–Angular frequency
t –Instantaneous time
ωt –Phase

4. :angularfrequencyORangularvelocity
t:time
I
0
:peakcurrent
V
0:peakvoltage
(2f)
IIsint
VVsint
o
o
T
1
f

5. 1.Instantaneous value:It is the value of alternating current and voltage at an instant t.
2.Peak value:Maximum values of voltage E
0and current I
0in a cycle are called peak values
3.Mean or average value of a.c.:It is defined as that value of direct current which sends the
same charge in a circuit in the same time as is sent by the given alternating current in its half time
period.
4.Root –mean-square (rms) or effective or virtual value of a.c.:It is defined as that
value of direct current which produces the same heating effect in a given resistor as is produced
by the given alternating current when passed for the same time
5.Phase difference Between the EMF (Voltage) and the Current in an AC Circuit:A
diagram that represents alternating current and voltage of the same frequency as rotating vectors
(phasors) alogwithproper phase angle between them is called a phasor diagram.
6.Phase: It is that property of wave motion which tells us the position of the particle at any
instant as well as its direction of motion. It is measured either by the angle which the particle
makes with the mean position or by fraction of time period.
7.Phase angle : Angle associated with the wave motion (sine or cosine) is called phase angle.
IfI
ois the peak value of alternating current andI
avgis the average value of current, thenI
oandI
avgare related as,
I
avg= 0.637I
o

6. 9. Lead: Out of the current and emf the one having greater phase angle will lead
the other e.g., in equation
i= i
0
sin ωt+
??????
�
and e = e
0
sin ωt,
the current leads the emf by an angle .
10. Lag : Out of current and emf the one having smaller phase angle will lag the
other. In the above equations, the emf lags the current by.

7. Phasor diagrams--A phasor is a straight line drawn in such a way that its length is related to
the amplitude of the sine wave represented, and its angular position relative to other phasors is
related to the phase difference between the quantities.
The phasor represented by the arrow is rotating in an anticlockwise direction about the centre.
Phasor diagrams
•Phasor diagrams are the representations of voltage-current relationship in AC circuits.
•A phasor is a vector capable of rotating about the origin with (angular velocity)‘ω’.
•The vertical component of phasor will represent the sinusoidally varying quantity.
•Considering V = V
msinωtthen the vertical component represents the instantaneous value of voltage.
•The magnitude(length of the vector) of the phasor is the peak value at that instant of time.
•In certain circuits when current reaches its maximum value after emf becomes maximum then
current is said to lag behind emf
•When current reaches its maximum value before emf reaches its maximum then current is said to
lead the emf
Advantages of phasor diagram:-
It is not possible to represent the complicated relationship between the voltage and currents with the help of graphs . In
that case phasor diagrams are used.

8. Five Rules for Drawing Phasor Diagrams.
Rule 1.The length of the phasor is directly proportional to the amplitude of the wave depicted.
Rule 2.In circuits which have combinations of L, C & R in SERIESit is customary to draw the
phasor representing CURRENT horizontally, and call this the REFERENCE phasor. This is because
the current in a series circuit is common to all the components.
Rule 3.In parallel circuits, where L, C and R are connected in parallel.The phasor representing the
SUPPLY VOLTAGE is always drawn in the REFERENCE direction. This is because in a parallel circuit
it is the supply voltage that is common to all components.
Rule 4.The direction of rotation of all phasors is considered to be ANTICLOCKWISE.
Rule 5.In any one diagram, the same type of value (RMS, peak etc.) is used for all phasors, not a
mixture of values.

10. phase relationship between voltage and current, learn this simple word called ‘CIVIL’,
i.ein capacitor current leads voltage and voltage leads current in inductor.
C I V I L
capacitor current voltage current inductor
R
E= E
0sin ωt
R
E= E
0sin ωt
E= E
0sin ωt
L
E= E
0sin ωt
C

11. •When an alternating current passed through a moving coil galvanometer it shows no deflection ,this is
because for one complete cycle mean value of alternating current is zero as AC flows in one direction during
one half cycle and in opposite direction during another half cycle.
•But mean value of A.C is finite over half cycle.
•So, mean or average value of AC is defined either for positive half cycle or for negative half cycle
•During next half cycle mean value of ac will be equal in magnitude but opposite in direction.
•Always remember that mean value of AC over a complete cycle is zero and is defined over a half cycle of AC
Average Value (or Mean Value) of Alternating Current
The Average value or mean value of alternating current over any half cycle is defined as that value of steady current which would sent
the same amount of charge through a circuit in the time of half cycle as is sent by the AC through the same circuit, in the sametime.
IfI
ois the peak value of alternating current andI
avgis the average value of current, thenI
oandI
avgare related as,
I
avg= 0.637I
o
Average Value (or Mean Value) of Alternating Voltage
Average value or mean value of alternatinge.m.f.over a half cycle is that value of constante.m.f.which should same amount of charge
through a circuit in the time of half cycle, as is sent by alternatinge.m.f.through the same circuit in the same time.
IfV
ois the peak value of alternatinge.m.f.andV
avgis the average value ofe.m.f., thenV
oandV
avgare related as,
V
avg= 0.637V
o

12. dq= I dt
= I
0 sin ωt dt
q = ∫ I
0sin ωt dt
0
T/2
q = 2 I
0/ ω= 2 I
0T / 2π= I
0T / π
Mean Value of AC, I
m= I
av= q / (T/2)
Average or Mean Value of Alternating emf:
Note: Average or Mean value of alternating current or emf is zero over a cycle as the + veand –vevalues
get cancelled.
E
m= E
av= 2 E
0/ π= 0.637 E
0= 63.7 % E
0
I
m= I
av= 2 I
0/ π= 0.637 I
0= 63.7 % I
0

13. Root Mean Square value of Alternating Voltage
The root mean square value of alternatinge.m.f.is defined as that value of steady voltage; which would generate the same amount of
heat in a given resistance in a given time, as is done by the alternatinge.m.f., when applied to the same resistance for the same time.
Root mean square value of alternating current (V
rms)and maximum value of alternating current (V
o) are related as,V
rms= 0.707V
o
Root Mean Square value of Alternating Current
Root mean square value of alternating current is defined as that value of steady current, which would generate the same amount of
heat in a given time, as is done by the AC, when passed through the same resistance for the same time.
Root mean square value of alternating current (I
rms)and maximum value of alternating current (I
o) are related as,
I
rms= 0.707I
o
RMS value of a.c. The rms value of alternating current is defined as that value of the steady
current, which when passed through a resistor for a given time, will generate the same
amount of heat as generated by an alternating current when passed through the same resistor
for the same time. The rms value is also called effective value of an a.c. and is denoted by Irms
when an alternating current i=I
osinωtflows through a resistor of resistance R, the amount of
heat produced in the resistor in a small time dt is dH= ??????
�
R dt. We know that alternating
current is given I = I
osinωt
The total amount of heat produced in the resistance in one complete cycle is

14. H =
�
??????
??????
�
Rdt
??????=
�
??????
??????
�
�
�??????�
�
߱ݐܴ݀ݐ
??????= ??????
�
�
ܴ
�
??????(�−??????���??????�)
�
݀ݐ
??????=
??????
�
�
ܴ
�
[
�
??????
݀ݐ−
�
??????
(??????���??????�)dt]
�
??????
(??????���??????�)dt=0
??????=
??????
�
�
ܴ
�
T
But this heat is also equal to the heat produced by rms value of AC in the same resistor (R) and in the same
time (T),
??????= ??????
���
�
ܴ??????
Thus ??????
���
�
ܴ??????=
??????
�
�
ܴ
�
T
I
rms= I
eff=
??????
�
√2
= 0.707 I
0= 70.7 % I
0
Root Mean Square orVirtual orEffective Valueof Alternating emf:
E
rms= E
eff= E
0/ √2 = 0.707 E
0= 70.7 % E
0
Note:1. Root Mean Square value of alternating current or emf can be calculated over any period
of the cycle since it is based on the heat energy produced.
2. Do not use the above formulae if the time interval under the consideration is less than one
period.

15. power
dcaveragepower
ac
I
2
RI
2
aveR
IIave
I
rms
Ther.m.s(rootmeansquare)currentmeansthe
square root ofthe averagevalue ofthecurrent

16. Direct Current Alternating Current
1.Electron flow in one direction.
1.Electron flows in both directions.
2.Magnitude remains constant. 2.Magnitude varies with time.
3.Can be stored in batteries. 3.Cannot be stored.
4.E.g. batteries 4.AC generators & mains
Comparison between AC and DC

17. ADVANTAGES OF A.C. OVER D.C.
•The generation of A.C. is cheaper than that of D.C.
•Alternating voltage can be easily stepped up or stepped down by
using a transformer.
•A.C. can be easily converted into D.C. by rectifier. D.C. is converted to
A.C. by an inverter.
•A.C. can be transmitted to a long distance without appreciable loss.

18. Resistor:Resistorsaredenotedbytheletter“R”.Aresistorisanelementthatdissipatesenergymostlyinformofheat.It
willhaveaVoltagedropacrossitwhichremainsfixedforafixedvalueofcurrentflowingthroughit.
Capacitor:Capacitorsaredenotedbytheletter“C”.Acapacitorisanelementwhichstoresenergy(temporarily)inform
ofelectricfield.Capacitorresistschangesinvoltage.Therearemanytypesofcapacitors,outofwhichtheceramic
capacitorandtheelectrolyticcapacitorsaremostlyused.Theychargeinonedirectionanddischargeinopposite
direction
Inductor:Inductorsaredenotedbytheletter“L”.AInductorisalsosimilartocapacitor,italsostoresenergybutis
storedinformofmagneticfield.Inductorsresistchangescurrent.Inductorsarenormallyacoilwoundwireandisrarely
usedcomparedtotheformertwocomponents.

19. Reactance
The opposition offered by an inductor or by a capacitor in the path of flow of alternating current
is called reactance.
Reactance is of two types
(i)Inductive Reactance(X
L)--Inductive reactance is the resistance offered by an inductor.
Inductive reactance
(X
L) = Lω= L2πf = L2π / T
Its unit is ohm. X
L∝ f
For direct current, X
L= 0 (f = 0
(ii)Capacitive Reactance(X
c)--Capacitive reactance is the resistance offered by an
inductor
Capacitive reactance,
X
c= 1 / Cω= 1 / C2πf = T / C 2π
Its unit is ohm X
c∝ 1 / fsss
For direct current, X
c= ∞ (f = 0)

20. Impedance
The opposition offered by an AC circuit containing more than one out of three
components L, C and R, is called impedance (Z) of the circuit.
Impedance of an AC circuit, Z = √R
2
+ (X
L–X
C)
2
Its SI unit is ohm.
Power in an AC Circuit
The power is defined as the rate at which work is being in the circuit.
The average power in an AC circuit,
P
av= V
rmsi
rmscos θ
= V / √2 i/ √2 cos θ = Vi / √2 cos θ
where, cos θ = Resistance(R) / Impedance (Z) is called the power factor 0f AC
circuit.
Current and Potential Relations
Here, we will discuss current and potential relations for different AC circuits.

21. (i)Pure Resistive Circuit (Rcircuit) --AC Circuit containing Resistor
only
When an AC is passed through a circuit containing (ideal) resistor only, then, alternating current
and alternatinge.m.f.are in phase andV=IR
When only resistance is in an ac circuit Consider a simple ac circuit consisting
of resistor of resistance R and andac generator, According to Kirchhoff’s loop
law at any instant , the algebraic sum of the potential difference around a
closed loop in a circuit must be zero
E –??????
??????= 0
E –IR = 0
E0 sinωt–IR = 0
I =
E
o
sinωt
R
-----1
I
o
sin ωt=
E
o
sinωt
R
I
o
=
E
o
R
t
0
π 2π 3π 4ππ/2 3π/2 5π/2 7π/2 θ= ωt
E
0
I
0
E= E
0sin
ωtI = I
0sin ωt
E
0
I
0
ωt
y
x
0
E
,I
R
E= E
0sin ωt
T/4 T/2 3T/4 T 5T/4 3T/2 7T/4 2T
E
0
I
0
ωt
x
0
R
E= E
0sin ωt

22. Where I
o
is the maximum current I
o
= E
o
/R From above equations, we see that the
instantaneous voltage drop across the resistor is
V = I
o
R sinωt---(2)
We see in equation (1) and (2) I and V both vary as sinωtand reach their maximum values at
the same time as shown in graph they are said to be in phase.
(a) Alternating emf, E = E
o
sin ωt
(b) Alternating current, I = I
o
sin ωt
(c) Alternating emf and alternating current both are in the same phase.
(d) Average power decay, (P) = E
v
. I
v
(e) Power factor, cos θ = 1

23. AC Circuit with a Pure Inductor:
When AC is passed through a circuit containing (ideal) inductor only, then,
alternating current lags behind alternatinge.m.f.by a phase angle of π/2.
It represents the effective opposition of the coil to the flow of alternating
current. It is denoted byX
L.
X
L= ωL= 2 πfL
Inductive reactance increases with increase in frequency i.e.,X
L∝f
According to Kirchhoff’s loop law at any instant , the
algebraic sum of the potential difference around a closed loop
in a circuit must be zero
E –??????
??????= 0
Induced emf in the inductor is -L
dI
dt
sInorder to maintain the flow of current, the applied emf must be equal
and opposite to the induced emf.
Inductance (L) can not decrease Direct Current. It can only decrease
E= E
0sin ωt
L
X
L
f
0

24. T/4 T/2 3T/4 T 5T/4 3T/2 7T/4 2T
t
E
,I
E= E
0sin ωt
I = I
0sin (ωt -π/ 2)
I = ∫ (
E
0
L
)sin ωt dt
I = (
E
0
ωL
)( -cos ωt )
I = I
0sin (ωt -π/ 2)
(where I
0= (
E
0
ωL
)and X
L= ωL =
E
0
I
0
)
X
Lis Inductive Reactance.
Its SI unit is ohm.
I
0
Current lags behind emf by π/2 rad.
0
π 2π 3π 4ππ/2 3π/2 5π/2 7π/2
θ= ωt
E
0
E = L
dI
dt
E
0sin ωt = L
dI
dt
dI = (
E
0
L
)sin ωt dt
y
(a) Alternating emf, E = E
o
sin ωt
(b) Alternating current, I = I
o
sin (ωt–π /
2)
(c) Alternating current lags behind
alternating emf by π / 2.
(d) Inductive reactance, X
L
= Lω= L2πf
(e) Average power decay, (P) = 0
(f) Power factor, cos θ = cos 90°= 0
x
0
x
E
0
ωt
π/2
I
0
E = L
dI
dt
E
0sin ωt = L
dI
dt

25. (iii)Pure Capacitive CircuitWhenAC is passed through a circuit containing (ideal) capacitor
only then, alternating current leads lead alternating voltage by a phase angle of 90
o
.
Capacitance (C) allows AC to flow through it but blocks DC.s
Inductive capacitance:
Effective opposition of the capacitor to the flow of alternating current is known as capacitive reactance.
It is denoted byX
C
X
C=
�
????????????
=
�
2πf??????
Inductive capacitance decreases with increase in frequency i.e.,Xc∝
�
f
On applying Kirchhoff’s rule to this circuit, we get E –??????
??????= 0
??????
??????= E
??????
??????= E
o
sin ωt
Where ??????
??????is the instantaneous voltage drop across the capacitor. From the definition
of capacitance
??????
??????= q/C, and this value of ??????
??????substituted into equation gives
(a) Alternating emf, E = E
o
sin ωt
(b) Alternating current, I = I
o
sin (ωt+ π /
2)
(c) Alternating current leads alternating emf
by π / 2.
(d) Inductive reactance, X
c
=
�
????????????
=
�
2πf??????
(e) Average power decay, (P) = 0
(f) Power factor, cos θ = cos 90°= 0
E= E
0sin ωt
C
E= E
0sin ωt
q = CE = CE
0 sin ωt
q = C E
o
sin ωt

26. y
E
0
ωt
(where I
0= E
0/ (1 / ωC) and
X
C=
�
ω??????
=
E
0
I
0
X
Cis Capacitive Reactance.
Its SI unit is ohm.
I
0
π/2
x0
Current leads the emf by π/2 radians.
T/4 T/2 3T/4 T 5T/4 3T/2 7T/4 2T
t
0
π 2π 3π 4ππ/2 3π/2 5π/2 7π/2θ= ωt
E
,IE
0
I
0
E= E
0sin ωt
I = I
0sin (ωt + π/ 2)
Charging and Discharging of a Capacitor
When the capacitor is connected to an ac source, it limits or regulates
the current, but does not completely prevent the flow of charge. The
capacitor is alternately charged and discharged as the current reverses
each half cycle.
I =
dq
dt
=
d
dt
[CE
0 sin ωt]
I = [E
0/ (
�
ω??????
)] ( cos ωt )
I = I
0sin (ωt + π/ 2)
X
C
f
0
Xc∝
�
f

27. (iv)R –C Circuit
SERIES R-C Circuit Now consider an ac circuit consisting of resistance R and
a capacitor of capacitance C in series with an ac source generator
E = E
o
sin ωt
I = E
o
/ 2 sin (ωt–φ)
Z = √R
2
+ (1 / ωC)
2
tan φ = –1 / ωC/ R
Current leading the voltage by φ
V
2
= V
2
R
-V
2
C
Suppose in phasor diagram, current is taken along positive direction.
The ??????
??????is also along positive x-direction as there is no phase difference between
??????
??????and ??????
??????. While ??????
??????will be along y direction as we know that current lags behind
the voltage by ??????�
??????
V = ??????
??????+ ??????
??????
= iR+ (i??????
??????) V
= I Z
Here Z = R + j??????
??????= R + (1/߱??????) is called as impedance of the circuit. Impedance
plays the same role in ac circuit as the ohmic resistance does in DC circuit. The
modulus of impedance is
|�| = √??????
�
+ (߱ܮ)
�
The potential difference leads the current by an angle
R
E= E
0sin ωt
C
x
0
??????
??????
??????
??????
??????

28. ??????= ݐ��−1 |
??????
??????
??????
??????
|
= ݐ��−1 (
??????
??????
ܴ
) ??????
= ݐ��−1 (
1/߱??????
ܴ
)
= ݐ��−1 (
1/�??????�??????
ܴ
)
i)If L = 0 then tan??????=0 or ??????= �
??????
Voltage and current are in same phase because circuit will be purely resistive in nature .
ii)If R = 0 then tan??????=∞or ??????= ??????�
??????
In this condition voltage will lead over the current by 90 degree because circuit will be purely
inductive in nature.

29. L-R Circuit
Now consider an ac circuit consisting of a resistor or resistance R and
an inductor of inductance L in series with an ac source generator
Suppose in phasor diagram, current is taken along positive direction.
The ??????
??????is also along positive x-direction as there is no phase
difference between ??????
??????and ??????
??????. While ??????
??????will be along y direction as we
know that current lags behind the voltage by ??????�
??????
V = ??????
??????+ ??????
??????= iR+ (i??????
??????) V= iZ
Here Z = R + j??????
??????= R + (ωL) is called as impedance of the circuit.
Impedance plays the same role in ac circuit as the ohmic resistance
does in DC circuit. The modulus of impedance is
|�| = √??????
�
+ (߱ܮ)
�
The potential difference leads the current by an
angle ??????= ݐ��−1 |
??????
??????
??????
??????
|
= ݐ��−1 (
??????
??????
ܴ
) ??????
= ݐ��−1 (
߱ܮ
ܴ
)
=ݐ��−1 (
2??????�ܮ
ܴ
)
V
x
0
R
E= E
0sin ωt
L
??????
??????
??????
??????
??????
i)If L = 0 then tan??????=0 or ??????= �
??????
Voltage and current are in same phase because circuit
will be purely resistive in nature .
ii)If R = 0 then tan??????=∞or ??????= ??????�
??????
In this condition voltage will lead over the current by 90
degree because circuit will be purely inductive in nature.

30. AC Circuit with L, C, Rin Series Combination
Consider an ac circuit consisting of resistance R, capacitor of capacitance C and an inductor of
inductance L are in series with ac source generator
Suppose in a phasor diagram current is taken along positive x-direction. Then V
R
is along positive
x-direction, V
L
along positive y-direction and V
C
along negative y-direction, as potential difference
across an inductor leads the current by 90 in phase while that across a capacitor, lags by 90
For a series LCR circuit driven by voltageV=V
m
sin ωt, the current is given byI=I
m
sin (ωt‒ϕ). Here we make an
assumption thatX
L
>X
C
Above relation is graphically shown in the figure given below
Here,e.m.f.is leading the current by phase angleϕandZis called impedance of the circuit and is measure in ohm.
E= E
0sin ωt
C
L R
V
RI
π/2
π/2
-V
C
V
L
V
RI
π/2
0
V
C
V
L
V
C
V
L
V
RI
V
L

31. E= E
0sin ωt
C
L R
1)In R, current and voltage are in phase.
2)In L, current lags behind voltage by π/2
3)In C, current leads the voltage by π/2
V
L -V
C
V
RI
E
Φ
E = √ [V
R
2
+ (V
L–
V
C)
2
]
The applied emf appears as Voltage drops V
R, V
Land V
Cacross R, L and C respectively.
E = √[V
R
2
+ (V
L–V
C)
2
]
Ohms law current =
??????������
���??????����??????�
I =
E
√[R
2
+ (X
L–X
C)
2
]
Z = √[R
2
+ (X
L–X
C)
2
]
Z = √[R
2
+ (ω L –
�
????????????
)
2
]
tan Φ=
X
L–X
C
R
tan Φ=
(ω L –
�
????????????
)
Ror
V
RI
π/2
π/2
-V
C
V
L
V
RI
π/2
0
V
C
V
L
V
C
V
L
V
RI
V
L
V
R = iR
V
L= iX
L
V
C= iX
C

32. ortan Φ=
X
L–X
C
R
tan Φ=
ωL –1/ωC
R
Special Cases:
Case I: When X
L> X
Ci.e. ωL > 1/ωC,
tan Φ= +veor Φis +ve
The current lags behind the voltage or emf by phase angle Φand the LCR circuit is inductance -dominated
circuit.
Case II: When V
L< V
C then X
L< X
Ci.e. ωL < 1/ωC,
tan Φ= -veor Φis –ve
The current leads the voltage or emf by phase angle Φand the LCR circuit is capacitance -dominated
circuit.
Case III: When V
L= V
Cthen X
L= X
Ci.e. ωL = 1/ωC,
tan Φ= 0 or Φis 0°
The current and the voltage or emf are in same phase. The impedance does not depend on the frequency of
the applied emf. LCR circuit behaves like a purely resistive circuit.
The root mean square voltage (V
rms
) cannot be added arithmetically to the applied root mean square voltage,
i.e.,V
rms
≠V
L
+V
C
+V
R
??????= ݐ&#3627408462;&#3627408475;−1 (V
L− V
C)/V
R
??????= ݐ&#3627408462;&#3627408475;−1 ( X
L− X
C)/ܴ
??????= ݐ&#3627408462;&#3627408475;−1 ( ߱ܮ− 1 /߱??????)/ܴ

33. SERIES L –C –R
The steady current is given by
The peak current is
It depends on angular frequency ω of ac source and it will be maximum when
I =
V
0
√[R
2
+ (X
L–X
C)
2
]
????????????&#3627408475;(߱ݐ+ ??????)
I =
V
0
√[R
2
+ (ω L –
&#3627409359;
????????????
)
2
]
????????????&#3627408475;(߱ݐ+ ??????)
I
0=
V
0
√[R
2
+ (ω L –
&#3627409359;
????????????
)
2
]

34. (ω L –
&#3627409359;
????????????
) = 0
߱= √
&#3627409359;
????????????
And corresponding frequency is
??????=
߱
2ߨ
=
1
2ߨ
√
&#3627409359;
????????????
This frequency is known as resonant frequency of the given circuit.
At this frequency peak current will be ??????
&#3627409358;=
??????
&#3627409358;
??????
This resistance R in the LCR circuit is zero, the
peak current at resonance is ??????
&#3627409358;=
??????
&#3627409358;
??????
It means, there can be a finite current in pure LC circuit
even without any applied emf. When a charged capacitor is connected to pure inductor This
current in the circuit is at frequency
??????=
1
2ߨ
√
&#3627409359;
????????????

35. L –C –R Circuit
(a) Alternating emf, E = E
o
sin Ωt
(b) Alternating current, I = I
o
sin (Ωt±θ)
(c) Alternating current lags leads behind alternating emf by ω.
(d) Resultant voltage, V = √V
2
R
+ (V
L
–V
C
)
2
(e) Impedance, Z = √R
2
+ (X
L
–X
C
)
2
(f) Power factor, cos θ = R / Z = R / √√R
2
+ (X
L
–X
C
)
2
(g) Average power decay, (P)= E
V
I
V
cos θ

36. Power in AC Circuit with L, C, R:
Instantaneous Power = E I
= E
0I
0sin ωt sin (ωt + Φ)
= E
0I
0[sin
2
ωtcosΦ+ sin ωt cosωt cosΦ]
E= E
0sin ωt I = I
0sin (ωt + Φ) (where Φis the phase angle between emf and current)
If the instantaneous power is assumed to be constant for an infinitesimally small time dt, then the work
done is dW= E
0I
0[sin
2
ωt cosΦ+ sin ωt cosωt cosΦ]
Work done over a complete cycle is
W = ∫ E
0I
0[sin
2
ωtcosΦ+ sin ωt cosωt cosΦ]dt
0
T
W = E
0I
0cos Φx
??????
&#3627409360;
Average Power over a cycle is P
av= W / T
P
av= (
E
0I
0
&#3627409360;
) cos Φ
P
av= (
E
0
√&#3627409360;
I
0
√&#3627409360;
)cos Φ
(where cos Φ=
??????
&#3627408513;
= R /√ [R
2
+ (ω L –
&#3627409359;
????????????
)
2
]is called Power Factor)
P
av= E
vI
v cos Φ
In case of steady current the rate of doing work is given by, P = VI
In an alternating circuit, current and voltage both vary with time, so the work done by the source in time interval
dt is given by dW= VI dt
Suppose in an ac, the current is leading the voltage by an angle φ . Then we can write

37. E
v
Power in AC Circuit with R:
In R, current and emf are in phase.
Φ= 0°
P
av= E
vI
vcos Φ= E
vI
vcos0°=E
vI
v
Power in AC Circuit with L:
In L, current lags behind emf by π/2.
Φ= -π/2
P
av= E
vI
vcos (-π/2) = E
vI
v(0)=0
Power in AC Circuit with C:
In C, current leads emf by π/2.
Φ= + π/2
P
av= E
vI
vcos (π/2) = E
vI
v(0)=0
Note:
Power (Energy) is not dissipated in Inductor and Capacitor and hence they
find a lot of practical applications and in devices using alternating current.
P
av= E
vI
v cos Φ
Wattless Current or Idle
Current:
I
v
I
v cos Φ
I
v sin Φ
Φ
90°
The component I
vcos Φ
generates power with E
v.
However, the component
I
vsin Φdoes not
contribute to power along
E
vand hence power
generated is zero.This
component of current is
called wattless or idle
current.
P = E
vI
vsin Φcos 90°= 0

38. Apply
(i)averagepower,
(ii)instantaneouspower,
(iii)powerfactor,
inAC circuitconsistingofR,RC,RLandRCLin
series.
PIV
cos
P
r

P
av
P
aIV
I
rmsV
rmscosP
av
•Power factor is a way of measuringhow efficiently electrical power is being used within a
facility's electrical system
??????= V
rmsI
rms??????&#3627408476;????????????This can also be written as,
Here P = I
2
Z cosφ
Z is impedance,
the term cosφis known as power factor
wherecosis
calledthe powerfactor
of theACcircuit,
P
risthe
averagereal powerandI
2Z
iscalledthe
apparent power

39. •Inan accircuit, the power
is only dissipatedbya
resistance,noneis
dissipatedbyinductanceor
capacitance
•From the phasor diagram
ofthe RCLseriescircuit
ω
V
L
V
V
L V
C
•Then
V
VVcos
Wegetcos
R
P
avIVcosandVIZ
P
avI
2
ZcosP
r
RV
V

I
C

40. •Powerfactorisdefinedas
•From
•thepowerfactoralso canbe
calculatedby usingthe equation
V
RIR
VIZ

below
cos
Z
cos
R

2
L C
VIR
2
XX
•When=0
o
(cos=+1),thecircuit
iscompletelyresistiveorwhenthe
circuitisinresonance(RCL)
•When=+90
o
(cos =0),the
circuitiscompletelyinductive
•When=-90
o
(cos =0),thecircuit
iscompletelycapacitive
P
aI
2
Z
P
r

P
r
cos

41. Resonance in AC Circuit with L, C, R:
When X
L= X
Ci.e. ωL = 1/ωC, tan Φ= 0 or Φis 0°and
Z = √[R
2
+ (ωL –1/ωC)
2
] becomes Z
min= Rand I
0max= E/ R
i.e. The impedance offered by the circuit is minimum and the current is maximum. This condition is called
resonant condition of LCR circuit and the frequency is called resonant frequency.
At resonant angular frequency ω
r ,
ω
rL = 1/ω
rCor ω
r= 1 / √LC orf
r= 1 / (2π√LC)
ω
r
I
0max
ω
0
R
1
R
2
R
3
I
0
I
0max / √2
ω
r -∆ωω
r + ∆ω
Band width = 2 ∆ ω
Quality factor (Q –factor) is defined as the ratio of resonant frequency to band width.
Q = ω
r / 2 ∆ ω
orQ = ω
rL / RorQ = 1 / ω
rCR
Q = V
L/ V
RorQ = V
C/ V
R
Resonant Curve & Q -Factor:
It can also be defined as the ratio of potential drop across either the
inductance or the capacitance to the potential drop across the resistance.
R
1< R
2< R
3
Q-factor The selectivity or sharpness of a resonant circuit is measured by
the quality factor or Q factor. In other words it refers to the sharpness of
tuning at resonance.

42. •Choke Coil:
1.An inductive coil used for controlling alternating current whose self-inductance
is high and resistance negligible, is called choke coil.
2.The power factor of this coil is approximately zero.
3.It controls current without consuming any power.
•A choke coil is a pure inductor. Average power consumed per cycle is zero in a
choke coil.
•A DC motor connects DC energy from a battery into mechanical energy of
rotation.
•An AC dynamo/generator produces are energy from mechanical energy of
rotation of a coil.
•An induction coil generates high voltages of the order of 1OS V from a battery.
It is based on the phenomenon of mutual induction.