CLASS IX MATHS PPT

15,469 views 40 slides Sep 10, 2018
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About This Presentation

Volume and surface area


Slide Content

PowerPoint presentation

What it is

it is rectangle

What it is

it is square

What it is

it is triangle

What it is

it is hexagon

Which type of figures these are

These are plane figures or 2 dimensional figures

What it is

it is cuboid

What it is

it is cube

What it is

it is cylinder

Which type of figures these are

These are called solid figures or 3d figures

HOW THESE SOLID FIGURE ARE MADE UP OF

THESE SOLID FIGURES ARE MADE UP OF PLANE SURFACES OR PLANE FIGURES

Side 2 Bottom Back Top Side 1 Front Side 2 Bottom Back Top Side 1 Front Length (L) Breadth (B) Height (H) Cuboid

WHEN WE TAKE THE AREA OF THESE PLANE FIGURES AS A SUM , THEN IT IS CALLED THE SURFACE AREA OF THE SOLID FIGURES.

NOW LET US DISCUSS THAT HOW TO FIND THE SURFACE AREAS OF CUBOID

The net L L L L B H H H H L B B B B B H H

H B L H B H L L L H B L H B H L L Total surface Area

Total surface Area = L x H + B x H + L x H + B x H + L x B + L x B = 2 ( LxB ) + 2( BxH ) + 2( LxH ) = 2 ( LB + BH + LH )

NOW LET US DISCUSS ABOUT THE SURFACE AREA OF CUBE

WHAT IS THE DIFFERENCE BETWEEN A CUBOID AND A CUBE

THE NET FOR THE CUBE

Cube L L L Total surface area = 2(LxL) + 2(LxL) + 2(LxL) = 6L 2

AREA OF FOUR WALLS . THIS IS ACTUALLY THE AREAS OF THE SURFACES WHERE THE HEIGHT IS INVOLVED . THIS AREA IS ALSO CALLED THE LATERAL SURFACE AREA IN CASE OF CYLINDER THIS PART IS CALLED THE CURVED SURFACE AREA BECAUSE THIS PART IS CURVED IN CASE OF CYLINDER

LSA OF CUBOID=2(L*H) +2(B*H) = 2(L+B)H LSA OF CUBE =L 2 + L 2 + L 2 + L 2 = 4 L 2

PRACTICE QUESTION 1. FIND THE SURFACE AREA OF CUBOIDAL BOX HAVING THE MEASUREMENT 10cm X 5cm X2cm.

SOLUTION S A OF CUBOID = 2(LB+BH+HL) = 2(10*5 + 5*2 + 2*10) = 2(50+10+20) = 2*80 =160 CM 2 .

PRACTICE QUESTION 2 FIND THE SIDES OF A CUBE WHOSE SURFACE AREA IS 600 CM 2 .

SOLUTION S A OF CUBE = 6a 2 600cm 2 = 6 a 2 100 cm 2 = a 2 TAKING SQUARE ROOT BOTH SIDE 10 cm = a EACH SIDE = 10cm.

LEARNING ACHIEVEMENT TEST 1. APLASTIC BOX 1.5 cm LONG 1.25 cm WIDE AND 65 cm IS TO BE MADE. IT IS OPENED AT THE TOP. IGNORING THE THICKNESS OF THE PLASTIC SHEET, DETERMINE : (A) THE AREA OF THE SHEET REQUIRED FOR MAKING THE BOX (B) THE COST OF THE SHEET FOR IT, IF A SHEET MEASURING 1m 2 COSTS Rs 20. 2. THE LENGTH , BREADTH AND HEIGHT OF A ROOM ARE 5m, 4m AND 3m RESPECTIVELY. FIND THE COST OF WHITEWASHING THE WALLS OF THE ROOM AND THE COST OF CEILING AT THE RATE OF Rs 7.50 PER m 2 . 3. THE FLOOR OF A RECTANGULAR HALL HAS A PERIMETER 250m. IF THE COST OF PAINTING THE FOUR WALL AT THE RATE OF Rs 10 PER m 2 IS Rs 15000, FIND THE HEIGHT OF THE HALL.

Home Assignment DISCUSS ABOUT THE DIAGONALS OF CUBOID AND CUBE

THANK YOU
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