A
B
A secant is a line that
intersects a circle at exactly
two points. (Every secant
contains a chord of the circle.)
T
A tangent is a line that intersects a circle at
exactly one point. This point is called the
point of tangency or point of contact.
Secant and Tangent Segments
A tangent segment is a point of a tangent line
between the point of contact and a point outside the
circle.
A secant segment is the part of a secant line that
joins a point outside the circle to the farther
intersection point of the secant and the circle.
T
B
Tangent segment
A
B
RAR is the secant segment.
The external part of a secant segment is the part
of a secant line that joins the outside point to the
nearer intersection point.
A
B
R
BR is the external part.
Theorem
When two chords intersect, the chords break
into segments that are equal when
multiplied.
A
B
C
D
X
XDCXXBAX
Theorem
When chords intersect, the chords break
into segments that are equal when
multiplied.
A
B
C
D
X
XDCXXBAX
8
3
4
6
Theorem
When chords intersect, the chords break
into segments that are equal when
multiplied.
A B
C
D
X
XDCXXBAX
10
8
4
K
Theorem
When chords intersect, the chords break
into segments that are equal when
multiplied.
A B
C
D
X
XDCXXBAX
10
8
4
K
5K
Theorem
When two secants intersect a circle, the
segments of the secants (the chord and
the whole secant ) are equal when
multiplied together. MQMPMOMN
Theorem
When two secants intersect a circle, the
segments of the secants (the chord and
the whole secant ) are equal when
multiplied together. MQMPMOMN
10
6
8
X
648166
886106
X
X
SCALETO
DRAWNNOTPICTURE
1
Theorem
When two secants intersect a circle, the
segments of the secants (the chord and
the whole secant ) are equal when
multiplied together. MQMPMOMN
10
6
8
X
4
832
64896
648166
886106
X
X
X
X
X
SCALETO
DRAWNNOTPICTURE
1
Theorem
A tangent and a secant
2
CDGDDF
CDCDGDGF
Theorem
A tangent and a secant
2
CDGDDF
CDCDGDDF
30
25 X
Theorem
A tangent and a secant
2
CDGDDF
CDCDGDDF
X
24
12
Theorem
A tangent and a secant
2
CDGDDF
CDCDGDDF
X
24
12
36
12432
14412576
121224
2
x
x
x
x
Example 4: Using Properties of Tangents
HK and HG are tangent to F. Find HG.
HK = HG
5a – 32 = 4 + 2a
3a – 32 = 4
2 segments tangent to
from same ext. point
segments .
Substitute 5a – 32 for
HK and 4 + 2a for HG.
Subtract 2a from both sides.
3a = 36
a = 12
HG = 4 + 2(12)
= 28
Add 32 to both sides.
Divide both sides by 3.
Substitute 12 for a.
Simplify.
Check It Out! Example 4a
RS and RT are tangent to Q. Find RS.
RS = RT
2 segments tangent to
from same ext. point
segments .
x = 8.4
x = 4x – 25.2
–3x = –25.2
= 2.1
Substitute 8.4 for x.
Simplify.
x
4
Substitute for RS and
x – 6.3 for RT.
Multiply both sides by 4.
Subtract 4x from both sides.
Divide both sides by –3.