quarter 2 simple and compound interest.docx

lesson plan in simple and compound interest

1. GRADES 11
DAILY
LESSON Plan
School Dominador Abang Memorial NHS Grade Level 11- STAR
Teacher Catherine D. Saldevia Learning Area General Mathematics
Teaching Dates and
Time
January 10, 2024
8:20 – 9:20
Quarter 2
nd
Quarter
OBJECTIVES
A. CONTENT
STANDARD
The learners and understands of key concepts of compound Interest
B. PERFORMANCE
STANDARD
The learners investigate, analyze and solve problems involving compound interest.
C. LEARNING
COMPETENCES
The learners solve problems involving simple and compound interest. ( M11GM-IIb-2 )
D.LEARNING
OBJECTIVE
a.Define compound interest.
b.Differentiate simple and compound interest.
c.Compute and solve problems involving compound interest; and
Make the best decision in handing certain problem involving money resources.
I. CONTENT Problem Solving Involving Maturity Value and Compound Interest
II. LEARNING
RESOURCES
General Mathematics book pp. 144-150
General Mathematics Learners Materials pp. 162-167
III. PROCEDURES
Teacher’s Activity Student’s Activity
Reviewing Previous
Lesson Ask the students to complete the table using the formula illustrated on the left.

2. Well done! You have mastered our previous lesson. This time we will proceed to the next topic.
Answer: a). Php 15, 000.00
b). 9 %
A.Activities Activity 1
Pix Mystery Word
Instructions:
1.Group the students into
2.Show pictures displaying time, save, invest, money, interest.
3.The group gives first the correct answer will receive a point.
4.Let the students name the pictures that will be flashed on the screen.
5.The group garnered the higher points will be declared as winner.

In what situations do we use those words?

Answer: Time
Answer: Save
Answer: Invest
Answer: Interest
Answer: Money
Time, save, invest, money, interest are
words used in loans or depositing money
in a banks and other cooperative groups.

3. ( Including banks in the Locality )
Activity 2: Together, we can Solve it!
Instructions:
1.The learners will be divided into four groups. Assign a leader, encoder, time keeper,
presenter, and research runner.
2.An activity sheet will be distributed to each group.
3.Each group will work on the same items in the worksheet for 8 minutes.
4.Guide questions are provided in the worksheet to direct the learners in their learning
task.
5.Each group will write their output on manila paper and present for 3 minutes.
Suggested Rubric
Note: allow the learners to formulate their own rubric or revise the suggested one.
Category Exceptional (10
points )
Admirable ( 5
Points )
Acceptable ( 3
Points)
Attempted ( 2
Point )
Content 90-100 % data
and evidence
gathered and
presented
75-99% data
and evidence
gathered and
presented
50-74 % data
and evidence
gathered and
presented
Below 50%
data and
evidence
gathered and
presented
Time
management
Finished on
time
Finished task
after 30
minutes of the
given time
Finished after
1 hour of the
allotted time
Did not
finished the
task
Teamwork Accepts ideas
of others; able
to
compromise;
100% of the
members are
on task.
Accepts most
ideas without
negative
comments;
able to
compromise;
75% of the
members
work on task.
Unwilling to
compromise;
50% of the
members work
on task.
One person
does all the
work; 25% of
the members
work on task.
Problem No. 1

4. Arthur borrowed P40, 000.00 at 6% simple interest for a period of 1 year. At the end of one
year, how much must he pay ____________.
Problem No. 2
If Arthur did not pay back the loan and the interest by the end of the first year and he
wanted to continue the loan for another year at the same rate, then he would owe P40, 000.00
plus interest incurred during the first year of loan. How much must he pay at the end of the
second year? ________________
Problem No. 3
At the end of the second year, Arthur was not able to pay his loan and the interest again.
The lender gave him another year under the same condition, how much must he pay at the end
of the third year? _______________
Answer: Php 42, 000.00
Answer: 44, 944.00
Answer: 47, 640.64
B.Analysis Have the learners answer these questions:
1.How did you find the problem?
2.How did you come up with your answer?
3.Did this problem happen in your family?
4.How did you come up with a solution to the group?
Say: Let us summarize your work by completing the table.
Note: ( both the teacher and the learners will work on the table )
Principal at the
start of the year
Interest Amount at the end of the year
First YearP40, 000.00 40, 000.00 x 0.06 x 1 =
P2,400.00
P40, 000.00 + 2,400.00= P42,
400.00
Second
year
P42, 000.00 42, 000.00 x .0.06 x 1 =
P2, 544.00
P42, 400.00 + 2, 544.00 = P44,
944.00
Third yearP 44, 944.00 44, 944.00 x 0.06 x 1 =
P2696.64
P 44, 944.00 + 2, 696.64 = P 47,
640.64
(Learners have different answer on this
questions)

5. A Have the learners answer the question below.
1.What can you say on the principal and the amount added to it every year if payment is
not made regularly?
2.What pattern can you see in the determining the amount to be paid at the end of the
year from first year up to third year?
3.Would it be helpful for you to apply for a loan? Support your answer.
4.How would you describe this type of transaction?
5.Can you give the formula in computing compound interest?
6.How about the amount to be paid on the maturity date?
Answer: The principal amount are not the
same (increasing Speedily) as well as the
amount of the interest added, if payment
is not made regularly.
Answer: The interest represented by 1 + r
is multiplied by itself according to the
maturity period expressed in years is
multiplied to original amount (Principal)
Answers Maybe Yes or No
Answer: This transaction involves
compound interest
Answer: I
c
=F−P
Answer: F=P(1+r)
t
C.Abstraction Compound interest (I
c) ( or compounding interest) is interest calculated on the initial principal and
on the accumulated interest of previous periods of a deposit or loan.
Thought to have originated in 17
th
century, Italy, compounded interest can be thought of as
“Interest on interest” and will make a sum grow at a faster rate than simple interest, which is
calculated only on the principal amount.
The rate at which compound interest depends on the frequency of compounding such that
the higher the number of compounding periods, the greater the compound interest. Thus,
the amount of compound interest accrued on Php 100, 000.00 compounded at 10% annually

6. will be lower than that on Php 100,000.00 compounded at 5% semi-annually over the same
period.
Maturity Value or Future value (F) – amount after t years that the lender receives from the borrower
on the maturity date.
Compound Interest = Total amount of principal and interest in future ( or future value ) less Principal
amount at present ( or present value )
I
c
=F−P
Maturity (Future) Value and Compound Interest (Compounded Annually)
F ¿P(1+r)
t
Where,
P= principal or present value F= maturity (future)Value at the end of the term
r=interest rate t= term/time in years I
c = compound interest
D.Application Activity 3: Problem Solving
Have the students to solve this problem: ( note: Solutions should be presented )
Find the Maturity value and the compound interest. If Php10, 000.00 is compounded annually
at an interest rate of 2% in 5 years.
Given: P=10,000.00
r= 2% or 0.02
t= 5 years
find: a. Maturity value
b. compound interest
Solutions:
(a). F ¿P(1+r)
t
F=10,000.00(1+0.02)
5
F=10,000.00(1.1040808032)
F=11,040.81

7. Now, You learned already about compound interest. Can you differentiate it with simple
interest?
Activity 4: Save and Invest
Each learner will make a “ Alkansya” Or “ Alkansya Bamboo” and each of them they will
deposit any amount each day and open it at the end of the month. The money that they will
save will be the basis of their performance of this topic. Learning for this was for them to know
if how much was the rate and the saving money will they earn. (Note: this activity can be used
in Araling Panlipunan 9: Napahahalagahan ang pag-iimpok at pamumuhunan bilang isang salik
ng ekonomiya)
(b).I
c
=F−P
I
c= 11,040.81 – 10,000.00
I
c= 1, 040.81
The future value F is Php 11, 040.81 and
the compound interest is Php 1,040.81
The major difference between simple
interest and compound interest is that
simple interest is based on the principal
amount. In contrast, compound interest is
based on the principal amount and the
interest compounded for a cycle of the
period.
IV. Additional activity

8. Prepared by:
CATHERINE PD. SALDEVIA
Teacher II
Noted by:
RODOLFO F. ALEMANIA JR.
Officer-In-Charge